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3 years ago

If a baby's leg pops out at 11:59PM but his head doesn't come out until 12:01, which day was he born on?

Mathematics

2 answers:

dangina [55]3 years ago

7 0

When he is fully out of the mothers womb and that the doctor can verify that the baby is alive

Ostrovityanka [42]3 years ago

6 0

The day the leg popped out at 11.59 pm

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The weights of adobe bricks used for construction are normally distributed with a mean of 3 pounds and a standard deviation of 0

dedylja [7]

Answer: a) 0.8413, b) 0.9987.

Step-by-step explanation:

Since we have given that

Mean = 3 pounds

Standard deviation = 0.25 pounds

n = 28 bricks

So, (a) What is the probability that all the bricks in the sample exceed 2.75 pounds?

$P(X>2.75)\\\\=P(z>\dfrac{2.75-3}{0.25}\\\\=P(z>\dfrac{-0.25}{0.25})\\\\=P(z>-1)\\\\=0.8413$

b) What is the probability that the heaviest brick in the sample exceeds 3.75 pounds?

$P(X>3.75)\\\\=P(z>\dfrac{3.75-3}{0.25})\\\\=P(z>\dfrac{0.75}{0.25})\\\\=P(z>3)\\\\=0.9987$

Hence, a) 0.8413, b) 0.9987.

4 0

3 years ago

What conclusion can be determined from the dot plot below?

EleoNora [17]

Answer:

The number of observations is 15.

3 0

3 years ago

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NO LINKS!!! Find the equation of the PARABOLA with a vertex at (-2, 6) and passing through the point (1, -3)

levacccp [35]

General equation of parabola

y=a(x-h)²+k

for vertex(h,k)

Now

$\\ \rm\Rrightarrow y=a(x+2)^2+6$

Put (1,-3) and find a

$\\ \rm\Rrightarrow -3=a(1+2)^2+6$

$\\ \rm\Rrightarrow -9=a(3)^2$

$\\ \rm\Rrightarrow -9=9a$

$\\ \rm\Rrightarrow a=-1$

equation of parabola

$\\ \rm\Rrightarrow y=-(x+2)^2+6$

7 0

2 years ago

Read 2 more answers

A scented candle is in the shape of a cylinder that is 8 inches tall. The diameter of the candle is 3.5 inches. Find the volume

blagie [28]

To find volume you use V=πr2h
V=3.14x1.75x2x8
answer: 76.97

5 0

3 years ago

Which of the following is equivalent to x^-1/2 1) -1/2x 2) -√x 3) 1/√x 4) -1/2x

irina [24]

Answer:

Option (3) is correct.

Step-by-step explanation:

We need to find the expression that is equivalent to $x^{-1/2}$ .

The property is : $x^{-a}=\dfrac{1}{x^a}$

Here, a = 1/2

So,

$x^{-1/2}=\dfrac{1}{x^{1/2}}$

We know that, $x^{1/2}=\sqrt{x}$

$\dfrac{1}{x^{1/2}}=\dfrac{1}{\sqrt{x} }$

So, $x^{-1/2}$ is equivalent to $\dfrac{1}{\sqrt{x} }$

Hence, the correct option is (3).

3 0

3 years ago