Lets operate is separate parts, the whole parts and the fractions:
9 1/6 - 3 5/8
= (9 - 3) + (1/6 - 5/8)
so now we have separated the operations, but now we need to get the fractions to the same denominator using the minimum common multiple of 6 and 8, which is 48 so we convert those fractions to be divided by 48:
1/6 = (8/8)(1/6) = (8*1)/(8*6) = 8/48
5/8 = (6/6)/(5/8) = (6*5)/(6*8) = 30/48
Lets substitute those fractions and subtract:
= (9 - 3) + (1/6 - 5/8<span>)
</span>= (9 - 3) + (8/48 - 30/48<span>)
</span>= (6) + (-22/48)
We have a negative fraction and have to subtract it from the whole part, we can convert the whole part to be divided by 48 as well, so the subtraction is easy:
6 = (48/48)(6) = (48*6)/(48) = 288/48
susbstitute:
<span>= (6) + (-22/48)
</span><span>= (288/48) + (-22/48)
</span><span>= 288/48 - 22/48
</span>= 266/48
= 5 26/48
= 5 13/24
Answer:
first, you want to start with the b (-3) graph on the y-axis. after that, since your x is 2 you will start from -3 on the y-axis and go up 2 and to the left once and keep doing that till you run out of space. then go back to the -3 on the y-axis and go down 2 and to the right once
A because 3 is rational, and it’s a natural and whole number because it’s about 0. It’s an integer because integers include negative and positive numbers.
Answer:Domain: all x-values that are to be used (independent values).
Step-by-step explanation:The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range. Domain: all x-values that are to be used (independent values).
Substitute 4 for x.
-|4-7|+3
-3+3
f(4) = 0
