Answer: 
Step-by-step explanation:
q(x) is increasing for 
.
p(x) is increasing for 
.
So, both functions are increasing for .
Answer:
m= -13/14
Step-by-step explanation:
use y=mx+b formula!
The inequality that represents the graph in the box is
Given :
The graph of the linear inequality
Lets pick two points from the graph to frame the linear equation
Slope intercept form of the equation is
Where m is the slope and b is the y intercept
y intercept is (0,6) from the graph
so b=6
Now we find out slope m using formula
Pick two points (0,6) and (2,0)
m=-3
So the equation is 
Now we check the inequality sign by testing any point on shaded area
lets pick (4,0)
lets plug in 4 for x and 0 for y
The inequality for the given graph is
we cannot use >= sign because we have dotted lines
Learn more : brainly.com/question/17203372
The labor-force participation rate of Belgium in 2017 was 77.78%
1.
Given:
Adult population = 4500
Number of employed in 2017 = <em>2800</em>
Number of Unemployed in 2017 = 700
Labor force participation rate = (employed + unemployed) / total population × 100
= (2800 + 700) / 4,500 × 100
= 3,500 / 4500 × 100
= 0.777777777777777 × 100
= 77.77777777777777%
Approximately, 77.78%
2.
Given:
Adult Population in 2016 = 3500
Number of employed in 2016 = 1800
Number of Unemployed in 2016= 600
Unemployment rate = unemployed population/ total labor force × 100
= 600 / 3,500 × 100
= 0.171428571428571 × 100
= 17.14285714285714%
Approximately,
17.14 %
Therefore, the unemployment rate of Japan in 2016 was 17.14%
Learn more about unemployment rate:
brainly.com/question/13280244
Answer:
We accept H₀ with the information we have, we can say level of ozone is under the major limit
Step-by-step explanation:
Normal Distribution
population mean = μ₀ = 7.5 ppm
Sample size n = 16 df = n - 1 df = 15
Sample mean = μ = 7.8 ppm
Sample standard deviation = s = 0.8
We want to find out if ozono level, is above normal level that is bigger than 7.5
1.- Hypothesis Test
null hypothesis H₀ μ₀ = 7.5
alternative hypothesis Hₐ μ₀ > 7.5
2.-Significance level α = 0.01 we will develop one tail-test (right)
then for df = 15 and α = 0,01 from t -student table we get
t(c) = 2.624
3.-Compute t(s)
t(s) = ( μ - μ₀ ) / s /√n ⇒ t(s) = ( 7.8 - 7.5 )*4/0.8
t(s) = 0.3*4/0.8
t(s) = 1.5
4.-Compare t(s) and t(c)
t(s) < t(c) 1.5 < 2.64
Then t(s) is inside the acceptance region. We accept H₀
