Answer and explanation:
<h2>h</h2>
<em>Subtract h + j + 2k = 16 by 4h + 4j + 2k = 5</em>
<em> </em> h + j + 2k = 16
-(4h + 4j + 2k = 5)
-3h - 3j = 11 <em>Then add 3j to both sides to get -3h alone</em>
-3h = 11 + 3j <em>Now divide both sides by -3 to get h</em>
h = =
<h2>j</h2>
<em>Plug in h and k to h + j + 2k = 16 </em>---> + j + 2(1) = 16
<em>Then add any like terms together</em> + 2j = 16
<em>Add on both sides</em> 2j = + 16
<em>Divide both sides by 2</em>
<em>You can divide a fraction by a fraction, so you do kcf</em> j = · =
<h2>k</h2>
<em>Multiply h + j + 2k = 16 by 2</em> ---> 2h + 2j + 4k = 32
<em>Then subtract 2h + 2j + 4k = 32 by 2h + 2j + k = 31</em>
<em> </em>2h + 2j + 4k = 32
-(2h + 2j + k = 31)
3k = 1 <em>Divide both sides by 3 to get k</em>
k = 1
Answer:
D
Step-by-step explanation:
1/12 X 110 = .0833333333 x 110 = 9.16
Answer:
Step-by-step explanation:
calculator???? srry
If the geometric series has first term and common ratio , then its -th partial sum is
Multiply both sides by , then subtract from to eliminate all the middle terms and solve for :
The -th partial sum for the series of reciprocal terms (denoted by ) can be computed similarly:
We're given that , and the sum of the first terms of the series is
and the sum of their reciprocals is
By substitution,
Manipulating the equation gives
so that substituting again yields
and it follows that