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3 years ago

Take a look at the picture. Please write an explanation to go with your answer. Thank you :)

Mathematics

1 answer:

9966 [12]3 years ago

3 0

Answer:

1/ 4

Step-by-step explanation:

The least amount of sap is represented on the horizontal Axis. The least amount means the treetgatvproduced the smallest amount of sap. Which will be the value to the left of the line dot plot as the values are ordered. Hence, we can say that three trees produced the smallest amount of sap which is 1/4

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SEE IMAGE PLEASE !!!

inysia [295]

Center of rhombus bisects 90°.

Sum of angles in triangle = 180°
x + x + 14 + 90 = 180
2x + 104 = 180
2 (x + 52) = 180
x = (180 ÷ 2) - 52
x = 90 - 52
x = 38°

4 0

2 years ago

Read 2 more answers

An air balloon begins it's decent to the ground at 1000 ft above the ground and falls at a rate of 50 ft per minute. Select all

Radda [10]

Answer:

The correct options are 3, 4 and 5.

Step-by-step explanation:

It is given that an air balloon begins it's decent to the ground at 1000 ft above the ground and falls at a rate of 50 ft per minute.

It means the initial height of air balloon is 1000. So, the y-intercept is (0,1000).

The ball falls at a rate of 50 ft per minute. So, the rate of change is

$m=-50$

The height of balloon is defined as

$h(x)=-50x+1000$ $[\because y=mx+b]$

Where, x is time in minutes.

The balloon will reach the ground when h(x)=0

$0=-50x+1000$

$50x=1000$

$x=20$

Therefore the options 3, 4 and 5 are correct.

4 0

3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$