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bezimeni [28]
3 years ago
8

this box can be packed with 48 unit cubes the edge length each unit cube is 1 meter what is the voume of the box

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
4 0
Since each cube has a volume of 1 cubic meter and the box and fit 48 unit cubes the volume of the box is 48  cubic meters.
Zina [86]3 years ago
3 0

Answer:

48\ m^{3}

Step-by-step explanation:

we know that

The volume of a cube is equal to

V=b^{3}

where

b is the side length of the cube

Find the volume of the unit cube

we have

b=1\ m

substitute

V=1^{3}=1\ m^{3} -----> volume of the unit cube

To find the volume of the box multiply 48 by the volume of the unit cube

so

48*1=48\ m^{3}

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Answer:

84

Step-by-step explanation:

7 0
3 years ago
There is a jar on the cabinet by the refrigerator. If Keona pours 114 ounces of water into the jar three times to fill it, how m
I am Lyosha [343]

The amount of quarts of water to fill the jar is 10.6875 quarts

To solve this problem effectively, we need to understand the concept of word problems.

<h3>What are word problems in mathematics?</h3>

Word problems in mathematics are questions that require a crucial understanding and application of mathematical principles to solve them effectively.

From the parameters given:

  • If 114 ounces of water is poured three times to fill the jar

Then, the total amount of ounces that fills the water is:

= 114 ounces × 3

= 342 ounces

From the dimensional analysis of measurements:

1 ounce = 0.03125 quarts

Thus, in quarts, 342 ounces will be:

\mathbf{=\dfrac{ (342 \  ounces \times 0.03125 \ quarts)}{1 \ ounce}}

= 10.6875 quarts

Learn more about word problems in mathematics here:

brainly.com/question/21405634

7 0
3 years ago
Squares with sides of length x are cut out of each corner of a rectangular piece of cardboard measuring 23 ft by 13 ft. The resu
trapecia [35]

Answer:

Step-by-step explanation:

Given that rectangle  has side length 23x13 feet.

When squares of side x are cut from all the four sides we have dimensions as

23-2x and 13-2x and height x

Volume =x(23-2x)(13-2x)

=x(299-72x+4x^2)\\=299x-72x^2+4x^3

Use derivative test

First derivative V'(x) V'(x)= 299-144x+12x^2\\V"(x) = -144+24x

Equate I derivative to 0

We get approximate value of x = 2.671, 9.329

Since width is 13 feet it cannot be 9.329

Hence x = 2.671

V"(x) = -80 <0

So maximum volume is

299x-72x^2+4x^3\\=299(2.671)-72(2.671)^2 +4(2.671)^3\\\\=361.186

5 0
3 years ago
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Hannah's answer is accurate

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4 years ago
Read 2 more answers
PLEASE HELP PLEASE IM GOING TO GIVE BRAINLIST
lara31 [8.8K]

Answer:

The answer is B or A

Step-by-step explanation:

7 0
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