The complete question in the attached figure
we know that
the equation of a sphere is
(x-h)²+(y-k)²+(z-l)²=r²
<span>let's assume that the center of the sphere is at the origin
</span>so
(h,k,l)-------> (0,0,0)
for r=16 m
(x-h)²+(y-k)²+(z-l)²=r²--------> (x)²+(y)²+(z)²=16²
for z=9 m
(x)²+(y)²+(9)²=16²--------> (x)²+(y)²=256-81--------> (x)²+(y)²=175
the radius of the circle is r=√175 m
so the area of the circle A=pi*r²-----> A=pi*175-----> A=549.5 m²
the answer is the area of the circle is 549.5 m²
Answer:
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Answer:
5+7x
Step-by-step explanation:
-3+5x+8+2x
8-3+5x+2x
5+7x
You multiply each term by each term when expanding double brackets, so:
-2x × 9x = -18x^2
-2x × -3y = 6xy
8y × 9x = 72xy
8y × -3y = -24y^2
Now you combine the like terms to get
-18x^2 + 78xy - 24y^2
I hope this helps!
Answer:
See below.
Step-by-step explanation:
(i) Sin 130 = sin ( 180 - 130) =<u> </u><u>sin 50 = k</u> (answer).
(ii) sin 50 = cos (90 - 50) = cos 40 = k.
The right angle with hypotenuse of 1 and the side opposite the angle whose sine is k has the adjacent side = √(1 - k^2) ( by the Pythagoras theorem),
so the sine of (90 - 50) = sin 40 = √(1 - k^2)/ 1.
Therefore<u> tan 40</u> = sin 40 / cos 40 = <u>√(1 - k^2) / k</u> (answer)
(iii) cos ( -220) = cos (360 - 220) = cos 140 = - cos 40
= -k.
Now since sec x = 1 / cos x :
<u>sec (-220</u><u>) = </u><u>-1/k</u> (answer).