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3 years ago

What is the graph of f(x)= 2x^2

1 answer:

3 0

Since this is a fairly small equation, it's pretty easy to plug in a few points to get ordered pairs and sketch a graph:

when x = 0...
f(0) = 2(0)^2
f(0) = 0
(0, 0)

when x = 1...
f(1) = 2(1)^2
f(1) = 2
(1, 2)

when x = -1...
f(-1) = 2(-1)^2
f(-1) = 2
(-1, 2)

from there, you can get a rough sketch of the graph just by plotting those points. essentially, it just looks "skinnier" than your typical parabola because the 2 out front makes the curve steeper.

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Honors Algebra II & Trig

Keith_Richards [23]

Answer:

The answer to your question is: f(g(1)) = $\sqrt{8}$

Step-by-step explanation:

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f(x) = $\sqrt{6- x}$

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3 years ago

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