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jasenka [17]
3 years ago
14

What is the graph of f(x)= 2x^2

Mathematics
1 answer:
konstantin123 [22]3 years ago
3 0
Since this is a fairly small equation, it's pretty easy to plug in a few points to get ordered pairs and sketch a graph:

when x = 0...
f(0) = 2(0)^2
f(0) = 0
(0, 0)

when x = 1...
f(1) = 2(1)^2
f(1) = 2
(1, 2)

when x = -1...
f(-1) = 2(-1)^2
f(-1) = 2
(-1, 2)

from there, you can get a rough sketch of the graph just by plotting those points. essentially, it just looks "skinnier" than your typical parabola because the 2 out front makes the curve steeper.
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Answer:

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2 years ago
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satela [25.4K]

Answer:

32.9

Step-by-step explanation:

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3 years ago
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mr_godi [17]

Answer:

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Step-by-step explanation:

for d) y(0) = 0 and y'(pi) =0

y(0) = C_1e^0cos(0)+ C_2 e^0 sin(0) = 0 \longrightarrow C_1 = 0

y(x) ' = C_1e^x cos(x) - C_1e^x sin (x) + C_2e^x sin(x) + C_2e^x cos(x)

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3 years ago
PLZ HELP I GIVE 15 POINTS
Natali [406]

Answer:

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Step-by-step explanation:

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The answer is now in improper fraction. When we convert it to mixed fraction we get the answer as <u>4 1/12. (Four, one by twelve).</u>

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Remove the parentheses and simplify 3a^2-6ab+3b^2-5(-6a^2+7ab-7b^2) 
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3 years ago
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