let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
Answer:
In my own opinion i time 104 and 72and if gives me7488
Answer
10.5
Step-by-step explanation:
Answer:
I'm almost positive it's .A but I'm not sure
