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photoshop1234 [79]
3 years ago
6

Select the relations that are functions.

Mathematics
1 answer:
liraira [26]3 years ago
7 0

Answer:

option A, C  and D

Step-by-step explanation:

Each relation is a function if each input has only one output

{a, 1), (6, 1), (C, 1)

This relation is a function because each input has only one output

{a, a),(a, b),(a, c)}

This relation is not a function because input 'a' has only three output

{(1, a), (2, a),(3, a)}

This relation is a function because each input has only one output

{a, a), (b, b), (C, c)}

This relation is a function because each input has only one output

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Answer:

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Step-by-step explanation:

To solve this, you need to evaluate the function at f(1), which just means that you have to plug in 1 for any x you see in the equation. For example, here f(1) = 2(1) + 2 which simplifies to 4. Next find f(5). By doing the same process you will find that this is 12. The problem asks for f(1) + f(5) so by putting those values in you will get 4+12=16. Hope this helps! :)

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2 years ago
Round 38.49 to the nearest whole number
AnnyKZ [126]
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3 years ago
What is the domain of y = cos ^-1x?
Bas_tet [7]

Answer:

Step-by-step explanation:

Correct option is

D

[1,(1+π)  

2

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f(x)=(1+sec  

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2

 

Hence range of f(x)=[1,(1+π)  

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ivolga24 [154]

Answer:

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