Write an expression for the sequence of operations. Add 3 to x, double what you have, then subtract 1 from the result

Slices of pizza for a certain brand of pizza have a mass that is approximately normally distributed with a mean of 67.7 grams an

Alexxx [7]

Answer:

a. s.e. = 0.338

b. The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 0.5871 or 58.71%

c. The probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams is 0.0694 or 6.94%

d. The sample mean of 62.75 would represent the 15th percentile

Step-by-step explanation:

1. Let's review the information provided to us to answer the question properly:

μ of the mass of slices of pizza for a certain brand = 67.7 grams

σ of the mass of slices of pizza for a certain brand = 2.28 grams

2. For samples of size 20 pizza slices, what is the standard deviation for the sampling distribution of the sample mean?

Let's recall that the standard deviation of the sampling distribution of the mean is called the standard error of the mean and its formula is:

μσs.e.= √σ/n, where n is the sample size.

s.e. = √2.28/20

s.e. = 0.338

3. What is the probability of finding a random slice of pizza with a mass of less than 67.2 grams?

Let's find the z-score for X = 67.2, this way:

z-score = (X - μ)/σ

z-score = (67.2 - 67.7)/2.28

z-score = 0.5/2.28

z-score = 0.22 (rounding to the next hundredth)

Now, using the z-table, let's find p, the probability:

p (z = 0.22) = 0.5871

The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 58.71%

4. What is the probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams?

Let's use the central limit theorem to find the z-score, this way:

z-score = X - μ/s.e

z-score = 67.2 - 67.7/0.338

z-score = -0.5/0.338

z-score = - 1.48

Now, using the z-table, let's find p, the probability:

p (z = -1.48) = 0.0694

5. What sample mean (for a sample of size 20) would represent the bottom 15% (the 15th percentile)?

For p = 0.150, let's find the z-score:

z-score = - 2.17

z-score = X - μ/s.e

- 2.17 = (X - 67.7)/2.28

- 4.95 = X - 67.7

X = 67.7 - 4.95

X = 62.75 (rounding to the next hundredth)

The sample mean of 62.75 would represent the 15th percentile

7 0

2 years ago

Write a simplified algebraic expression for each phrase or expression.

11Alexandr11 [23.1K]

I think it should be 15x

4 0

2 years ago

Read 2 more answers

What the answer to this problem

g100num [7]

The equation:

$(x-10)+40+(x-20)+3x=360\\\\(x+x+3x)+(-10+40-20)=360\\\\5x+10=360\ \ \ \ |-10\\\\5x=350\ \ \ \ |:5\\\\x=70$

8 0

2 years ago

The width of a rectangle is 4 less than half the length. if l represents the length, which equation could be used to find the wi

g100num [7]

W-4=1/2L
W=1/2L+4
This is the answer

5 0

3 years ago

Cesar had a part-time job last year. He worked every week for the year and made $23 an hour. He worked 28 hours each week. Cesar

Naddika [18.5K]

Answer:

D. $2,511

Step-by-step explanation:

First off, we need to write down the facts we know.

There are about 52.177 weeks in a year

Cesar works 28 hours each week

Cesar makes $23 an hour

There are 12 months in a year

Cesar has $3,360 after his monthly expenses

To figure out how many hours are in a "work year," multiply the number of work hours in a week by the number of weeks in a year. In other words, multiply Cesar's 28 hour work week by about 52.177 weeks. That makes 1,456 hours in his work year. That means he makes $33,492 a year. If you multiply $2,511 by the months in a year (12), you get $30132. Finally, subtract his annual salary by $30132 to get $3,360, which is what was left of Cesar's earnings after paying all of his monthly expenses.

5 0

3 years ago

Read 2 more answers