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4 years ago

What’s the answer ??????

Mathematics

1 answer:

Mashcka [7]4 years ago

8 0

The equation is 8.08 x 10^6
___________
4.0 x 10^6
first, you will need to reduce the fraction with 10^6
8.08/ 4
you will then convert the decimal number into a fraction
202/25/4
youll then simplify the above complex fraction
101/50
your answer will be 101/50 or 2 1/50 or 2.02
let me know if you have any further questions
:)

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Use the graph to find the limit (if it exists). If the limit does not exist, explain why.

Mandarinka [93]

Answer:

the limit does not exist

Step-by-step explanation:

As x approaches π/2 from below, tan(x) approaches +∞. A x approaches π/2 from above, tan(x) approaches -∞. These two limits are not the same, so the limit is said not to exist.

___

For a limit to exist, it must be the same regardless of the direction of approach.

6 0

4 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

Diane received 300 votes in the election for student council president. That was 60% of the students who voted election. How man

VikaD [51]

Answer:

500

Step-by-step explanation:

The problem statement tells you ...

300 = 0.60×voters

Dividing by the coefficient of the variable gives ...

300/0.60 = voters = 500

500 students voted in the election.

8 0

3 years ago

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Me ayudan a resolver unos problemas en word les adjunto el archivo

Rashid [163]

Hola! yo te ayudaria, pero no se en que. No tienes el problema para que yo lo resuelva. Lo siento si mi espanol no es bueno, estoy aprendiendo como escribir lo. Sorry-

3 0

3 years ago

PLS SOLVE THANK YOU FOR SOLVING IF YOU DO

Ugo [173]

Answer:

Since the triangles are congruent, AB=ED so AB=14

Angles F is congruent to angle C so F=39 degrees

Step-by-step explanation:

8 0

3 years ago

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