Answer: None (zero)
Step-by-step explanation:
Half life of the substance = 2 days
At the start, the substance life is 4 days
At the end of 4 days, there isn't any substance left
Multiply the base which is 18.65 and multiply it by the height which is 9 3/10 and then multiply by half and that estimates to B. 90 cm
Given :
- Base = 20 cm and 14 cm.
- Height = 5 cm.
To find :
Solution :
We know,
![{\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{1}{2 } \times (b_{1} + b_{2}) \times h} }}](https://tex.z-dn.net/?f=%7B%5Cqquad%20%5Cdashrightarrow%7B%20%5Cbf%7BArea_%7B%28Trapezoid%29%7D%3D%20%5Cdfrac%7B1%7D%7B2%20%7D%20%20%5Ctimes%20%28b_%7B1%7D%20%2B%20b_%7B2%7D%29%20%5Ctimes%20h%7D%20%7D%7D)
Now, Substituting the values :
![{\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{1}{2 } \times (20 + 14) \times 5} }}](https://tex.z-dn.net/?f=%7B%5Cqquad%20%5Cdashrightarrow%7B%20%5Cbf%7BArea_%7B%28Trapezoid%29%7D%3D%20%5Cdfrac%7B1%7D%7B2%20%7D%20%20%5Ctimes%20%2820%20%2B%2014%29%20%5Ctimes%205%7D%20%7D%7D)
![{\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{5}{2 } \times 34} }}](https://tex.z-dn.net/?f=%7B%5Cqquad%20%5Cdashrightarrow%7B%20%5Cbf%7BArea_%7B%28Trapezoid%29%7D%3D%20%5Cdfrac%7B5%7D%7B2%20%7D%20%20%5Ctimes%2034%7D%20%7D%7D)
![{\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{5}{ \cancel2 } \times \cancel{34}} }}](https://tex.z-dn.net/?f=%7B%5Cqquad%20%5Cdashrightarrow%7B%20%5Cbf%7BArea_%7B%28Trapezoid%29%7D%3D%20%5Cdfrac%7B5%7D%7B%20%5Ccancel2%20%7D%20%20%5Ctimes%20%20%5Ccancel%7B34%7D%7D%20%7D%7D)
![{\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}=5 \times 17} }}](https://tex.z-dn.net/?f=%7B%5Cqquad%20%5Cdashrightarrow%7B%20%5Cbf%7BArea_%7B%28Trapezoid%29%7D%3D5%20%5Ctimes%2017%7D%20%7D%7D)
![{\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}=85} }}](https://tex.z-dn.net/?f=%7B%5Cqquad%20%5Cdashrightarrow%7B%20%5Cbf%7BArea_%7B%28Trapezoid%29%7D%3D85%7D%20%7D%7D)
Therefore,
- <u>The area of the trapezoid is 85 cm²</u> .
Answer:
me neather
Step-by-step explanation: