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Svet_ta [14]
3 years ago
9

8x-5y=-118x−5y=−118, x, minus, 5, y, equals, minus, 11 xxx-intercept: \Big((left parenthesis ,,comma \Big))right parenthesis yyy

-intercept: \Big((left parenthesis ,,comma \Big))
Mathematics
2 answers:
SOVA2 [1]3 years ago
6 0
You need to put a picture on here instead of that.
Galina-37 [17]3 years ago
6 0
Will you add a picture please we don’t know what you are talking about!
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The experimental probability of getting a 3 on a number cube is 5/36. Which of the following is true about the event’s experimen
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The number 3 was rolled 5 times in 36 trials.

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4n + 1= 25 how do I solve this and show my work?​
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Answer:

n=6

Step-by-step explanation:

4n + 1= 25

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4n=25-1

Calculate

4n=25-1

Then divide on both sides

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Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv
ch4aika [34]

Answer:

Part 1) The function of the First graph is f(x)=(x-3)(x+1)

Part 2) The function of the Second graph is f(x)=-2(x-1)(x+3)

Part 3) The function of the Third graph is f(x)=0.5(x-6)(x+2)

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

f(x)=a(x-c)(x-d)

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-3)(x+1)

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

-4=a(1-3)(1+1)

-4=a(-2)(2)

a=1

therefore

The function is equal to

f(x)=(x-3)(x+1)

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

f(x)=a(x-1)(x+3)

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

8=a(-1-1)(-1+3)

8=a(-2)(2)

a=-2

therefore

The function is equal to

f(x)=-2(x-1)(x+3)

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-6)(x+2)

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

-8=a(2-6)(2+2)

-8=a(-4)(4)

a=0.5

therefore

The function is equal to

f(x)=0.5(x-6)(x+2)

3 0
4 years ago
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