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Alexxx [7]
3 years ago
12

How do I do I solve problems like this?

Mathematics
1 answer:
densk [106]3 years ago
7 0
A,b,b I think would be the answer
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Using the given points, determine the slope. (5,-6)and(2,15)
Hunter-Best [27]
Subtract the y-coordinates. This is the rise.
Subtract the x-coordinates in the same order. This is the run.
Slope = rise/run.

Subtract the y-coordinates: -6 - 15 = -21. rise = -21
Subtract the x-coordinates in the same order:5 - 2 = 3. run = 3

slope = rise/run = -21/3 = -7
6 0
3 years ago
Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
3[x]+9 what is the graph?
ipn [44]
So, you can do this one of two ways.

The first is knowing what the numbers in your equation represent:

For example: y=mx+b in this case "b" is 9. b is the y-value when x=0. So the first point on our graph is (0,9). Next we have to pick an xvalue to solve for another y-coordinate.

I chose x= -3. Plug x into the equation to get y.
y=3x+9
y=3(-3)+9
y=(-9)+9
y=0

So, our second point is (-3,0).

connect the points with a ruler to graph the line.

4 0
3 years ago
MARKING YOU BRAINLIST AND 5 STARS! A tire from Karen's car is shown below. Which is the closest to the distance traveled, in fee
Yuki888 [10]

Answer:

18.86 feet

Step-by-step explanation:

One rotation of the tire is equal to the circumference of the tire

The formula for circumference of a circle (remember that a tire is shaped as a circle) = πd

where

π = 22/7

d = diameter

The size of one revolution = 2 x 22/7 = 44/7 feet

The distance covered in one rotation of the tire is 44/7 feet

The distance covered in 3 rotations = (44/7) x 3 = 18.86 feet

3 0
2 years ago
The perimiter of each face of a rubiks cube is 22.2 centimeters. What is the length of and edge of the rubiks cube?
ivanzaharov [21]

Answer:

3.7 cm

Step-by-step explanation:

22.2 / 6 = 2.7

Hope that helps!

5 0
3 years ago
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