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3 years ago

Please hellppp me eeee

Mathematics

2 answers:

Anni [7]3 years ago

5 0

Answer:

Number 7 is A and Number 8 is D.

Elan Coil [88]3 years ago

4 0

Answer:

The correct answers are

A) 2+10h

D) 40

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Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Thus the given expression is simplified

8 0

3 years ago

Log In a survey of a town, 63% of residents own a car, 20% of residents own a truck, and 4% of residents own both a car and a tr

yan [13]

Answer:

Step-by-step explanation:

Let T= truck

C= Car

We are looking for the probability that someone owns a truck given that they own a car

P(T|C)

The conditional probability formula is as follows:

P(T|C)=(T∩C)/C

plugging in numbers..

.04/.63=6.3492% which rounds to 6%

4 0

3 years ago

Please help me in with these two questions Geometry.

horrorfan [7]

Answer:

#1 is A #2 is A

Step-by-step explanation:

5 0

2 years ago

Mark spent $21 on a magazine and some candy bars. If the magazine cost $5 and each candy bar cost $2, then how many candy bars d

Lana71 [14]

Answer:8 candy bars because 21-5=16/2=8 candy bars.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

1. Addition

nexus9112 [7]

Answer:

1. Exponent

2. Multiplication

3. Subtraction

4. Square root

5. Addition

6. Division?

Note: I am not very sure about my answer because of two things. 1. The proper order for operating is PEDMAS (Parentheses, Exponent, Multiplication, division, addition, and subtraction). There is no Square root in that operation so I will consider it in the middle. 2. There is no division operation in this problem.

4 0

3 years ago

Read 2 more answers