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Gemiola [76]
3 years ago
15

janet is three years older than her sister julie.janets brother is eight years younger than their sister julie.the sum of all of

their ages is 55 years
Mathematics
2 answers:
solniwko [45]3 years ago
6 0
Let's name Janet's age x

julie is then x-3 years old

and the brother is x-3-8=x-11

and all three of them: x+x-3+x-11 are 55

so we count:

2x-3+x-11=55
3x-3-11=55
3x-14=55

add 14 5o both sides:

3x=69

divide by 3:
x=23

so Janet is 23, Julie is 23-3=20 and the brother is 20-8=12 years old!





spayn [35]3 years ago
4 0
If Janet = Julie + 3
 Janet Bro = Julie - 8
  and Janet + Janet Bro + Julie = 55

Janet is 23.
Julie is 20.
Janet's brother is 13.
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Factor by grouping.......
Gekata [30.6K]

Answer:

A. (7n-1) (8n-1)

Step-by-step explanation:

56n^2 -8n-7n+1

56n^2 -8n       -7n+1

Factor out 8n from the first group   and -1 from the second group

8n (7n-1)     -1(7n-1)

Factor out the (7n-1)

(7n-1) (8n-1)

7 0
3 years ago
I need help solving this
nexus9112 [7]
Trs and tra by AA (you r correct)

7 0
3 years ago
Simplify 4(7-10)^/(-6)-5*(-2)
trasher [3.6K]
Use your calculator put all of them together then you’ll get your answer
8 0
3 years ago
Can someone help me with this question? You don’t really have to tell me the answer but just how to solve it.
Veronika [31]

part A

if the paperbacks are 40% less, that means 100% - 40% = 60%, they actually are 60% of the price of the hardcover ones.

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{60\% of 24.99}}{\left( \cfrac{60}{100} \right)249.99}\implies 14.994

part B

so, if they return it, they get 1/3 credit, if they try to sell it, is half off, which is more than 1/3.  22 got damaged.

\bf \stackrel{\textit{damaged books at half-price}}{(22\cdot 14.994)\cfrac{1}{2}\implies 164.934}~\hfill \stackrel{\textit{damaged books at one-third price}}{(22\cdot 14.994)\cfrac{1}{3}\implies 109.956} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 164.934 - 109.956 = 54.978~\hfill

part C

\bf \textit{First Day}~\hfill \stackrel{hardcover}{3(24.99)}+\stackrel{paperback}{8(14.994)}+\stackrel{damaged}{3\left( 14.994\cdot \frac{1}{2} \right)} \implies 217.413 \\\\\\ \textit{Second Day}~\hfill \stackrel{hardcover}{4(24.99)}+\stackrel{paperback}{5(14.994)}+\stackrel{damaged}{8\left( 14.994\cdot \frac{1}{2} \right)}\implies 234.906 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \boxed{17.493}

I don't think she is incorrect, $17.5 is close to $20, she didn't say it was exactly $20, just thereabouts, and 17.5 is around that much.

8 0
3 years ago
Given f(x) = 7x - 4 and g(x) = -3x + 2, find (f+g)(x)​
zalisa [80]

Answer:

<h2>(f+g)(x) = 4x - 2</h2>

Step-by-step explanation:

f(x) = 7x - 4

g(x) = -3x + 2

To find (f+g)(x) add g(x) to f(x)

That's

<h3>(f+g)(x) = 7x - 4 +  (- 3x + 2) \\  = 7x - 4 - 3x + 2 \\  = 7x - 3x -  4 + 2</h3>

We have the final answer as

<h3>(f+g)(x) = 4x - 2</h3>

Hope this helps you

5 0
3 years ago
Read 2 more answers
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