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3 years ago

11

Solve the inequality below. f2−9>−5

2 answers:

mylen [45]3 years ago

6 0

Answer:

f>2 or you could do f<-2

Step-by-step explanation:

f^2−9>−5

Add 9 to each side

f^2−9+9>−5+9

f^2 >4

f>2 or f<-2

Salsk061 [2.6K]3 years ago

5 0

Answer:

f>2 or f<-2

Step-by-step explanation:

f^2−9>−5

Add 9 to each side

f^2−9+9>−5+9

f^2 >4

Take the square root of each side, remembering to flip the sign of the inequality for the negative

f>2 or f<-2

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$\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{6})\qquad
(\stackrel{x_2}{-3}~,~\stackrel{y_2}{-9})
\\\\\\
slope = m\implies
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$\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
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\\\\
\cline{1-1}
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\\\\\\
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C
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4 years ago

Read 2 more answers

Please asap<br>for 10 points!

kari74 [83]

<h3>Given:</h3><h3>Large cone:</h3>

r= 8 cm
h= 20 cm

<h3>Small cone:</h3>

r= 4 cm
h= 10cm

<h3>Note that:</h3>

r: radius
h: height

<h3>To find:</h3>

The volume of the frustum of the given cone.

<h3>Solution:</h3>

Frustum is a part of a cone formed by cutting off the top by a parallel plane.

$\large\boxed{Formula: V= \frac{1}{3}\pi{r}^{2}h}$

Let's solve!

First, let's find the volume of the smaller cone.

Substitute the values according to the

formula.

$V= \frac{1}{3}×\pi×{4}^{2}×10$

$V= 167.5516082 \: {cm}^{3}$

Now, we can round off to the nearest hundredth.

The value in the thousandths place is smaller than 5 so we won't have to round up.

$\boxed{V= 167.55 \: {cm}^{3}}$

Next, let's find the volume of the bigger cone.

Substitute the values according to the formula.

$V= \frac{1}{3}×\pi×{8}^{2}×20$

$V= 1340.412866 \: {cm}^{3}$

Now, we can round off to the nearest hundredth.

The value in thousandths place is smaller than 5 so we won't have to round up.

$\boxed{V=1340.41 \: {cm}^{3}}$

Now, we can find the volume of the frustum.

We'll have to minus the volume of the smaller cone from the bigger cone.

$V= 1340.41-167.55$

$\large\boxed{V= 1172.86 \: {cm}^{3}}$

<u>Hence, the volume of the frustum is 1172.86 cubic centimeters.</u>

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2 years ago