All categories

3 years ago

Factor the expression

Mathematics

1 answer:

charle [14.2K]3 years ago

6 0

Hi

9k^2 + 24k + 16
= ( 3k + 4)(3k + 4)

Good luck

You might be interested in

Solve the equation for x and round your answer to the nearest hundredth.<br> 5x + 14 = 26

maks197457 [2]

5x + 14 = 26

subtract 14 on both sides

5x = 26 - 14

5x = 12

Divide 5 on both sides

x = 12/5

x = 2.4

That's only to the nearest tenth. To make it to the hundreth, just add another 0 at the end. It doesn't change the value of it.

x = 2.40 is your final answer.

7 0

3 years ago

I need answers 1-4 please!

madreJ [45]

1. Horizontal asymptotes: None
Vertical asymptote: x=-2
RD: 2
Domain: First picture
Range: first pic

2.HA: y=1
VA: x= -5 negative
RD: x= 5 no negative
Domain: second pic
Range second pic

3.HA: y=0
VA: x=-4,4
RD: none
D: 3rd pic
R: 3rd pic

4.HA: none
VA: x=3
RD: x=-2
D: 4th
R: 4th

I hope this helps!!!!!!!

8 0

3 years ago

Will give Brainly please help

s2008m [1.1K]

Answer:

B. 95º

Step-by-step explanation:

Supplementary angles are ones that add up to 180º.

So if angle 1 is 85º, then the equation would be:

(x-the measure of angle 2)

X + 85 = 180

Solve for x:

X + (85-85) = 180-85

X = 95.

Hope this helps! Have a great day!

3 0

3 years ago

Read 2 more answers

The probability that a civil servant own a car is 1/6,if two civil servants are selected at random.find the probability that

Elodia [21]

Answer:

The data we have is:

the probability that a civil servant own a car is 1/6

Two civil servants are selected at random.

a) The probability that each own a car.

Ok, here we have two events:

Person 1 haves a car.

Person 2 haves a car.

The probability of each of those events is the same, 1/6.

P1 = 1/6

P2 = 1/6

Now, the probability of both events happening at the same time is equal to the product of the individual probabilities.

P = P1*P2 = (1/6)*(1/6) = 1/36.

b) Only one has a car.

Suppose that Person 1 has the car and Person 2 has not a car.

The probability for person 1 is 1/6.

And for person 2, is the negation of having a car:

So if we have prob of having a car = 1/6

Then the probability of not having a car is = 1 - 1/6 = 5/6.

Then we have:

P1 = 1/6

P2 = 5/6.

The joint probability is:

P = P1*P2 = (1/6)*(5/6) = 5/36.

But we also have the case where person 1 does not have a car, and person 2 does have one, then we have a permutation, and the actual probability is two times the obtained above.

P = 2*(5/36) = 10/36

4 0

3 years ago

What is 5 2/9 plus 7 5/15

alina1380 [7]

47/9+110/15=705/135+990/135=1695/135=12 15/27

7 0

3 years ago

Read 2 more answers