Answer:
105
Step-by-step explanation:
(.5)πr²
to get the area of the shaded parts you have to subtract the area of the semicircle from the area of the rectangle




subtract the areas

≅ 
Answer:

Step-by-step explanation:
S = second; F = flying time.
Since it can flap its wings 30 times, each second, we have already found our answer. The relationship between flying time (Wing flaps) and seconds is 30. In other words, it beats it's wings 30 times each second. Which is what the question asks.
Now we just have to write the equation:

This is because the seconds are <u>dependent</u> on the flap of wings, so s would be the y value.
Hope it Helps!
<h2>
Answer:</h2>
<u>The answer is </u><u>(C) 4</u>
<h2>
Step-by-step explanation:</h2>
According to the rule of BODMAS
We will first do division then Multiplication then addition and in the last we do subtraction
So
12 ÷ 2 + 4 – 2 × 3 will be done as
= (12 ÷ 2) + 4( – 2 × 3)
= 6+4-6
= 4
Answer:
Area = 960 cm^2
Step-by-step explanation:
Perimeter (P) = 2 (l + w)
P = 2l + 2w
Let the length be 5x
Let the width be 3x
From the question, P = 128.
Therefore:
128 = 2l + 2w
Divide both sides by 2.
l + w = 64
Recall we said:
l = 5x
w = 3x
So then:
5x + 3x = 64
8x = 64
Divide both sides by 8
x = 64/8
x = 8.
Since x = 8
Length = 5x = 5*8 = 40cm
Width =3x = 3 * 8 = 24cm
Area of a RECTANGLE:
Area = length * width
Area = 40 * 24
Area = 960 cm^2
The first thing we must do for this case is find the scale factor.
We have then that for the larger side of both triangle, the scale factor is:

To find the other two sides, we must apply the scale factor on each side of the triangle FGH.
We have then:
For PQ
For QR
Answer:
You have that the lengths for the other two sides of triangle PQR are: