Question

Two hot air balloons are flying above a park . One ballon started at a height of 3,000 feet above the ground and is decreasing in a height at a rate of 40 feet per minute . The second ballon is rising at a rate of 50 feet per minute after beginning from a height of 1,200 feet above the ground .
Given that h is the height of the balloons after m minutes , determine which system of equations represents this situation .

Answer 1

H = 3000 - 40m (starts at 3000...decreasing at 40 ft per minute
h = 1200 + 50m (starts at 1200...rises 50 ft per minute

Answer 2

Answer:

Option A represented the system of equations.

Step-by-step explanation:

Two hot air balloons are flying above a park.

(1) Balloon (A) at a height 3000 ft. is decreasing in a height at a rate of 40 feet per minute.

If we draw a linear equation to represent the relationship it will be like

y = mx + c where c is y -  intercept or height of the balloon = 3000 ft.

Rate of decrease in height will represent the slope of the balloon

m = (-40)

So the equation will be  y = -40x + 3000

here y is height h and x represent time t.

We can rewrite the equation as  h = 3000 - 40t

(2) Similarly for second balloon slope is the rate of change in height of the balloon = +50 and height of balloon (y-intercept) = 1200 ft.

So equation will be h = 50 m + 1200

Therefore, Option A represented the system of equations.