An example should help you understand
(3 + 2) + (8 +1)
= 9* + 1) + (3 + 2)
= 3 + (2 + 8 + 1)
= 2 + 3 + (1 + 8)
all of these have the same sum.
Answer:
a) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
Answer: If four numbers are proportional, a : b = c : d, then the product of the extremes is equal to the product of the means. ad = bc
Answer:
x=10
Step-by-step explanation:
P+S=140
(5x+30)+80=140
5x+30=80
5x=50
x=10
For the training adaptation of maximum strength, 1 to 5 repetitions per set is recommended.
The one-repetition maximum test, also called a one-rep max or 1RM, is used to find out the heaviest weight you can lift just once.
If Maximal strength is desired, it is best achieved by performing repetitions at 85 to 100 % of the one-repetition maximum (1RM).
Formula to find the repetition is
weight used x (reps done x 0.33 + 1) = 1RM
so,
Reps done = {{1RM/weight used} - 1}/ 0.33
By this find the no of reps are recommended for maximum strength.
The maximum strength is achieved by doing the number of reps by 85 to 100% of the value of 1 RM.
So,
For the training adaptation of maximum strength, 1 to 5 repetitions per set is recommended.
Learn more about the MAXIMUM STRENGTH here
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