Y=5x+11 using the point-slope formula and simplifying
Distance from focus to vertex=distance from vertex to directix
from (6,2) to y=1, the distance is 1
the focus is 1/2 higher than the vertex
vertex=(6,1.5)
for
(x-h)^2=4p(y-k)
vertex=(h,k)
p=distance from vertex to directix
vertex=(6,1.5)
ditance=0.5
(x-6)^2=4(0.5)(y-1.5)
(x-6)^2=2(y-1.5) is the equation
or
y=0.5x^2-6x+19.5 or
y=0.5(x-6)^2+1.5
2x+2 < x+3
2x-x < 3-2
x <1
Let's solve for x.
3
x
+
5
y
=
10
Step 1: Add -5y to both sides.
3
x
+
5
y
+
−
5
y
=
10
+
−
5
y
3
x
=
−
5
y
+
10
Step 2: Divide both sides by 3.
3
x
3
=
−
5
y
+
10
3
x
=
−
5
3
y
+
10
3
Answer:
x
=
−
5
3
y
+
10
3
