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2 years ago

Help plz!!!!!!!!!!!!!

Mathematics

1 answer:

DedPeter [7]2 years ago

6 0

First part
Determine 2 points that pass through x + 2y = 5

(i) If x = 1
x + 2y = 5
1 + 2y = 5
2y = 4
y = 2

(ii) If x = 3
x + 2y = 5
3 + 2y = 5
2y = 2
y = 1

Two points that pass through this line are (1,2) and (3,1)

Second part
Determine 2 points that pass through 3x = 15 - 6y

(i) If x = 1
3x = 15 - 6y
3(1) = 15 - 6y
3 = 15 - 6y
6y = 15 - 3
6y = 12
y = 2

(ii) If x = 3
3x = 15 - 6y
3(3) = 15 - 6y
9 = 15 - 6y
6y = 15 - 9
6y = 6
y = 1

Two points that pass through this line are (1,2) and (3,1)

BOTH OF THE LINE pass through the same two points, that means the lines are the same because they overlap. Look at the attachment.

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Answer:

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Step-by-step explanation:

Given

$Highway = 31mi/gallon$

$City = 26mi/gallon$

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Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

$c + h = 10$ ---- gallons used

and

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In the first equation, make c the subject

$c = 10 - h$

Substitute 10 - h for c in the second equation

$31h + 26c = 285$

$31h + 26(10 - h) = 285$

Open bracket

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Collect like terms

$31h - 26h = 285 - 260$

$5h = 25$

Make h the subject

$h = \frac{25}{5}$

$h = 5$

Substitute 5 for h in $c = 10 - h$

$c = 10 - 5$

$c = 5$

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

$Highway = 31 * 5$

$Highway = 155\ miles$

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

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Sindrei [870]

Answer:

$\boxed{D = 69}$

Step-by-step explanation:

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Comparing it with the standard form of Quadratic Equation $ax^2+bx+c = 0$ , we get:

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