R= $42 rental cost per day
Mileage= $0.20 per mile
m= number of miles driven
Budget= $98 per day
EQUATION
$98> $0.20m + $42
SOLUTION
$98> $0.20m + $42
subtract 42 from both sides
$56> $0.20m
divide both sides by $0.20
280> m
They have to drive less than 280 miles per day to stay within their $98 budget.
SAME SOLUTION INEQUALITIES
Set up the equations with new numbers, substitute 280 for m and pick another variable to solve for. I chose to solve for total rental cost.
m= 280 miles per day
R= Rental cost per day
R> $0.10(280) + $50
R> $28 + $50
R> $78
Equation #1
$78> $0.10m + $50
----------
m= 280 miles per day
R= Rental cost per day
R> $0.18(280) + $44
R> $50.40 + $44
R> $94.40
Equation #2
$94.40> $0.18m + $44
ANSWER: 280> m; They have to drive less than 280 miles per day to stay within their $98 budget.
Equation #1: $78> $0.10m + $50
Equation #2: $94.40> $0.18m + $44
Hope this helps! :)
1/14 goes into 6 7/10, 93.8 times
Answer:
a at c place 45 degree b at a place 45 dgree cat b place 90 degree
Answer:
Average consumption ( mean ) = 9
MOE = 4
Step-by-step explanation:
We know that
CI ( 5 ; 13 )
and CI [ μ - MOE ; μ + MOE ]
From the above relations we get
μ - MOE = 5
μ + MOE = 13
Adding member to member these two equations we get
2*μ = 18
μ = 9 and MOE = 13 - 9
MOE = 4
Answer:
y >5
Step-by-step explanation:
−4y + 6 < −14
Subtract 6 from each side
−4y + 6-6 < −14-6
-4y < -20
Divide by -4. Remember to flip the inequality since we are dividing by a negative
-4y/-4 >-20/-4
y >5