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If the ratio is 5:3, then you divide 275 by 5, and then multiply it by 3. If you test the result, you'll find that the ratio fits.
Step-by-step explanation:
f(x)=2x²+3x+9
g(x) = - 3x + 10
In order to find (f⋅g)(1) first find (f⋅g)(x)
To find (f⋅g)(x) substitute g(x) into f(x) , that's for every x in f (x) replace it by g (x)
We have
(f⋅g)(x) = 2( - 3x + 10)² + 3(- 3x + 10) + 9
Expand
(f⋅g)(x) = 2( 9x² - 60x + 100) - 9x + 30 + 9
= 18x² - 120x + 200 - 9x + 30 + 9
Group like terms
(f⋅g)(x) = 18x² - 120x - 9x + 200 + 30 + 9
(f⋅g)(x) = 18x² - 129x + 239
To find (f⋅g)(1) substitute 1 into (f⋅g)(x)
That's
(f⋅g)(1) = 18(1)² - 129(1) + 239
= 18 - 129 + 239
We have the final answer as
<h3>(f⋅g)(1) = 128</h3>
Hope this helps you
<u>The commutative property is when you can change the order and it will be the same answer.</u>
<u>6 + 8 + 7 = 7 + 8 + 6</u> would be your answer.
Even though you have reflected this triangle, your side length would still be the same. Explanation: Reflection is when you take an object on your coordinate plain and put it somewhere else on the plain. So if side QR is 3 than side Q’R’ would also be 3. Hope this helps!
If the original side length is "s" and the original slant height is "h", the original surface area is
.. S = (base area) +(lateral area)
.. S = s² +(1/2)*(4s)*h
.. S = s(s +2h)
Now, if we make these replacements: s ⇒ 3s, h ⇒ h/5, we have
.. S' = (3s)(3s +2h/5)
.. S' = 9s² +(6/5)s*h . . . . . . . the formula for the modified area (in terms of original dimensions)
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Of course, in terms of the modified dimensions, the formula is the same:
.. S' = s'(s' +2h')
