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melamori03 [73]

3 years ago

6

Select all that apply. PLEASE HELP!!!!!

1 answer:

IrinaVladis [17]3 years ago

8 0

Answer: Goverment good

Step-by-step explanation:

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Which postulate or theorem justifies the following statement? If two angles are a linear pair, then they are supplementary angle

mojhsa [17]

I believe it is the linear pair theorem because the theorem is if two angles form a linear pair, then they are supplementary.

5 0

3 years ago

In the standard form of a circle (x-h)^2+(y-k)^2=r^2(x−h)

Gennadij [26K]

9514 1404 393
Answer:
Part A: 2 f2
Part B: draw a diagonal (AC, for example); 1 f12
Step-by-step explanation:
Part A:
The area of a parallelogram is given by the
formula
A=bh
where "b' is the length of the base, and 'h' is the
perpendicular distance between the bases.
Using the numbers shown on the diagram, the
area is
A = (3 ft)(2/3 ft) = 3-2/3 f12
A =2 ft2..... area of the parallelogram
Part B:
Typically, a polygon is partitioned into triangles
by drawing diagonals from one of the vertices. It
does not matter which one. (In a quadrilateral,
only one diagonal can be drawn from any given
vertex.) Here, the "base" of each triangle is the
same as the base of the parallelogram: 3 feet.
The "height" of each triangle is the same as the
height of the parallelogram: 2/3 ft.
The area of a triangle is given by the formula

7 0

3 years ago

When rabbits were introduced to the continent of Australia they quickly multiplied and spread across the continent since there w

Lady bird [3.3K]

Answer:

a. $y=6(1.7472)^x$

b. $y=6e^{0.558t}$

c.13.3 months

Step-by-step explanation:

a.-Given the first term at $t_0$ is 6 and the second term at $t_3$ is 32.

-Let's take rabbit population as a function of time to be

$y=ab^x$

where y is the population at time x and a the initial population at $t_0\\$

#We substitute our values to calculate the value of the constant b:

$y_x=ab^x\\\\y_3=ab^3\\\\32=6b^3\\\\b=1.472$

#Replace b in the population function:

$y=ab^x, b=1.7472,a=6\\\\\therefore y=6(1.7472)^x$

Hence, the regression for the rabbit population as a function of time x is $y=6(1.7472)^x$

b. The exponential function in terms of base $e$ is usually expressed as:

$A=A_0e^{kt}$

Where:

$A_0$ -is the initial population at $t_o$

$A$ -is the population at time t.

$k-$ is the exponential growth constant.

$e-$ the exponent

Our function in terms of base exponent is rewritten as:

$y=A_0e^{kt}$

#Substitute with actual figures to solve for t:

$y=A_0e^{kt}, y=32, xt=3, A_0=6\\\\32=6e^{3k}\\\\3k=In (32/6)\\\\k=0.5580$

Hence, the regression equation in terms of base e is $y=6e^{0.558t}$

c. We substitute y with any number higher than 10,000 to estimate the time for the rabbits to exceed 10,000.

-We know that $y=6e^{0.558t}.$

Therefore we calculate t as(take y=10001):

$y=6e^{0.558t}, y=10001\\\\10001=6e^{0.558t}\\\\1666.8333=e^{0.558t}\\\\0.558t= In 1666.8333\\\\t=13.2951$

Hence, it takes approximately 13.3 months for the population to exceed 10000

3 0

4 years ago

Which situation is best represented by the following equation?

liq [111]

Answer:

D

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Ellen wants to give 100 toys to each of 9 charities. In one week, she collects 387 toys. The next week, she collects 515 toys. H

jasenka [17]

Yes because she has collected 902 you have to add the two numbers

3 0

3 years ago