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MakcuM [25]
3 years ago
8

What is the answer for 2+2?​

Mathematics
2 answers:
Travka [436]3 years ago
7 0

Answer:

Pretty sure it's

disa [49]3 years ago
3 0

Answer:

4

Step-by-step explanation:

:)

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What is the distance between (-3, 4) and (4, 4)
svetoff [14.1K]

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7 units

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\sqrt{|-3-4|^{2}-|4-4|^{2}}

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What is the square root of 5
Zigmanuir [339]

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2.236

Step-by-step explanation:

you could estimate it to be between 2 and 3 (because 5 is between 4 and 9)

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5 0
3 years ago
Could you guys help me find the area of these please? i don't understand how to do this
vova2212 [387]

Answer:

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I am re-editing this

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7 0
3 years ago
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A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia
iogann1982 [59]
\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
t=0\qquad P=182
\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\

\bf P=182e^{kt}\qquad 
\begin{cases}
2002\impliedby \textit{8 years later}\\
t=8\qquad P=186
\end{cases}\implies 186=182e^{k8}
\\\\\\
\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k
\\\\\\
\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}

what's the population in 2004?  well,  from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004
3 0
3 years ago
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