2.333p=c
i am not sure really what you want but
Answer:
x = 50*e∧ -t/100
Step-by-step explanation:
We assume:
1.-That the volume of mixing is always constant 300 gallons
2.-The mixing is instantaneous
Δ(x)t = Amount in - Amount out
Amount = rate * concentration*Δt
Amount in = 3 gallons/ min * 0 = 0
Amount out = 3 gallons/min * x/ 300*Δt
Then
Δ(x)t/Δt = - 3*x/300 Δt⇒0 lim Δ(x)t/Δt = dx/dt
dx/dt = - x/100
dx/ x = - dt/100
A linear first degree differential equation
∫ dx/x = ∫ - dt/100
Ln x = - t/100 + C
initial conditions to determine C
t= 0 x = 50 pounds
Ln (50) = 0/100 * C
C = ln (50)
Then final solution is:
Ln x = - t/100 + Ln(50) or
e∧ Lnx = e ∧ ( -t/100 + Ln(50))
x = e∧ ( -t/100) * e∧Ln(50)
x = e∧ ( -t/100) * 50
x = 50*e∧ -t/100
A/4 = b/7 Cross multiply: 7a =4b Divide by b: (7a/b)=4 Multiply by 1/7: a/b =4/7
4/7 is your answer
Step-by-step explanation:
the answer is 10 ft. cuz 120 / 12 is 10
Answer:
5/12 hours
Step-by-step explanation:
Honon = 3 1/4 hours
Sequoia = 2 5/6 hours
How much more time did Honon spend on homework than Sequoia
= number of hours Honon spent - number of hours Sequoia spent
= 3 1/4 hours - 2 5/6 hours
= 13/4 - 17/6
= (39-34) /12
= 5/12 hours
