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Kay [80]
3 years ago
5

Solve this quadratic equation 2x^2+x-5 = 0

Mathematics
1 answer:
DIA [1.3K]3 years ago
3 0
2x^2+x-5=0
           +5 +5
2/2x^2+x=5/2
x^2+x=2.5
square root both sides
x+x=1.58
2/2x=1.58/2
x=0.79
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aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

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Part 2

\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 3

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We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity \sin^2(\theta)+\cos^2(\theta) = 1 in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

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