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Alenkinab [10]
4 years ago
11

Can someone help me find the radius? Thanks! :D

Mathematics
1 answer:
Crazy boy [7]4 years ago
7 0
The answer is D because u can find the radius from the number
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Answer:

a)  \bar X \sim N(40,\frac{5}{\sqrt{64}}=0.625)

b) P(39.6 \leq \bar X \leq 40.4)=0.4778

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent interest on this case, and for this case we know the distribution for X is given by:

X \sim N(\mu=40,\sigma=5)  

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

(a) What are the mean and standard deviation of the sampling distribution?

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(40,\frac{5}{\sqrt{64}}=0.625)

(b) What is the approximate probability that x will be within 0.4 of the population mean μ? (Round your answer to four decimal places.) P =

So for this case we want this probability:

P(40-0.4 \leq \bar X \leq 40+0.4)= P(39.6 \leq \bar X \leq 40.4)

And for this case we can use the z score given by this formula:

Z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this concept we got this:

P(\frac{39.6 -40}{\frac{5}{\sqrt{64}}} \leq \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}} \leq \frac{40.4 -40}{\frac{5}{\sqrt{64}}})

P(-0.64 \leq Z \leq 0.64) =P(z

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3 years ago

julsineya [31]
The answer is C.672 sq in. bescause you have to times 14 by 48 and get your area of 672.
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