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3 years ago

If 217 over 300 is written as a decimal, how many digits repeat?

Mathematics

1 answer:

mojhsa [17]3 years ago

7 0

I thnk the answer would be that one digit repeats (the 3) as the decimal is .7233333 and so on with the threes

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An angle measures 50° more than the measure of a complementary angle. what is the measure of each angle?

77julia77 [94]

We solve the equation: a = 50 + ( 90 - a );
Then, a = 140 - a;
2a = 140;
a = 140/2;
a = 70 (it is the measure of one angle);
90 - 70 = 20 (it is the measure of another angle);

3 0

4 years ago

Can someone explain To me how to do this and to figure out the answer for 14 and 15

Radda [10]

Do you know how to find area

8 0

3 years ago

What is the value of 6 (2b-4) When b=5

e-lub [12.9K]

Answer:

Step-by-step explanation:

Replace the 2b with 10 and then do the parenthesis, so 10-4=6

now multiply it with the 6 outside the parenthesis and you get 36

7 0

3 years ago

Read 2 more answers

In a large population, about 10% of people do not like the taste of cilantro, an herb used in cooking. A researcher takes a rand

bogdanovich [222]

Answer:

0.0019390

Step-by-step explanation:

10% of people do not like the taste of cilantro

A researcher takes a random sample of 15 people and surveys whether they like cilantro

Use the binomial distribution to compute the probability that exactly 6 of the people in the sample do not like cilantro.

Probability of success = 0.10 = p

Probability of failure = 0.9 =q

n = 15

r = 6

Formula : $P(X=r)=^nC_rp^r q^{n-r}$

$P(X=6)=^{15}C_6 (0.1)^6 (0.9)^{15-6}$

$P(X=6)=\frac{15!}{6!(15-6)!} (0.1)^6 (0.9)^{15-6}$

$P(X=6)=0.0019390$

Hence the probability that exactly 6 of the people in the sample do not like cilantro is 0.0019390

3 0

3 years ago

What is the equation of the quadratic function that has vertex (-3, 1) and passes through the point (-2, 4)?

Marat540 [252]

Vertex form: $y=a(x-h)^2+k$ , with (h,k) as the vertex.

For this, we will be using vertex form. Firstly, plug the vertex into the vertex form equation:

$y=a(x-(-3))^2+1\\y=a(x+3)^2+1$

Next, we need to solve for a. Plug in (-2,4) into the x and y coordinates to solve for a as such:

$4=a(-2+3)^2+1\\4=a(1)^2+1\\4=a+1\\3=a$

Putting our equation together,<u> it's $y=3(x+3)^2+1$ </u>

<u>*Additional section*</u>

Standard form: $y=ax^2+bx+c$

Converting to standard form as such:

$y=3(x+3)^2+1\\y=3(x^2+6x+9)+1\\y=3x^2+18x+27+1\\y=3x^2+18x+28$

8 0

3 years ago