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wlad13 [49]
2 years ago
15

What is the value of 6 (2b-4) When b=5

Mathematics
2 answers:
e-lub [12.9K]2 years ago
7 0

Answer:

36

Step-by-step explanation:

Replace the 2b with 10 and then do the parenthesis, so 10-4=6

now multiply it with the 6 outside the parenthesis and you get 36

Blizzard [7]2 years ago
6 0

Hi! I'm happy to help!

First of all, we need to substitute b into the expression.

6(2b-4)

6((2×5)-4)

Now we use the order of operations, or PEMDAS (Parenthesis, Exponents, Multiplication or Division, and Addition or Subtraction) to finish simplifying.

We see that 2×5 is inside two sets of parenthesis, so we solve that first

6((2×5)-4)

6((10)-4)

We cam remove the extra set of parenthesis because there isn't an expression inside of it any more.

6(10-4)

Now, we look inside of the parenthesis again and we see 10-4

6(10-4)

6(6)

The six next to the parenthesis has no sign next to it, which means to multiply.

6×(6)

Now we can remove the parenthesis.

6×6

Now, we just simply multiply.

6×6

36

To sum it up: <u>The value of 6 (2b-4) When b=5 is 36</u>

I hope this was helpful, keep learning! :D

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Answer:

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Step-by-step explanation:

Domain:\\\\2y-8\neq0\ \wedge\ y+4\neq0\ \wedge\ y^2-16\neq0\\\\2y\neq8\ \wedge\ y\neq-4\ \wedge\ y^2\neq16\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq\pm\sqrt{16}\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq-4\ \wedge\ y\neq4\\\\\boxed{y\neq-4\ \wedge\ y\neq4}\\\\===========================

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\dfrac{8(y+4)}{(y-4)(y+4)}+\dfrac{10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{8(y+4)+10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{use the distributive property}\\\\\dfrac{8y+32+10y-40}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{combine like terms}\\\\\dfrac{(8y+10y)+(32-40)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{18y-8}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\iff18y-8=14y+16\\\\18y-8=14y+16\qquad\text{subtract 14y from both sides}

4y-8=16\qquad\text{add 8 to both sides}\\\\4y=24\qquad\text{divide both sides by 4}\\\\y=8\in D

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