If you flip three fair coins, what is the probability that you'll get a tail on the first flip, a head on the second flip, and a
1 answer:
Answer:
<em>12.5%</em>
Step-by-step explanation:
<u>Probabilities</u>
When flipping three fair coins, we can get the following events, being H=Heads, T=Tails
We are looking for the probability of only one specific outcome: THT. The probability to get exactly that combination one out of 8 possible results, that is
The probability to get a tail on the first flip, a head on the second flip, and another tail on the third flip is 12.5%
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Answer:
2/7 ml
Step-by-step explanation:
When we have a solution expressed in Q mg/ml, the concentration is (Q/10)%.
For example, a solution of 3 mg/ml is a 3/10=0.3% concentration solution, a solution of 40 mg/ml is a 40/10=4% concentration solution.
<em>Why? </em>
Q mg/ml means that 1 ml of solution has Q mg of the drug or active component. So, 100 ml have 100*Q mg.
But 100*Q mg = Q/10 grams.
If a solution has Q/10 grams in 100 ml, then it is a (Q/10)% concentration.
Now, we have 5 ml of a solution that contains tobramycin, 3 mg/ml (each ml has 3 mg of tobramycin).
This means that the 5 ml contain 15 mg of tobramycin.
On the other hand, we have another solution S containing 40 mg/ml of tobramycin. This means that each ml of S contains 40 mg of tobramycin.
Let x be the amount of ml of S we have to add to our first 5 ml.
If 1 ml of S contains 40 mg of tobramycin, x ml contain 40*x mg.
If we add this x ml to our first 5 ml, we have 5+x ml containing 15+40*x mg of tobramycin.
Now, cross-multiply to get how much tobramycin contains 1 ml of this new solution.
5+x ml ____contain____15+40*x mg of tobramycin
1 ml ____contains____? mg
And we have
as a result, we have a solution of
We want to prepare a solution 0.5% in concentration.
Using what we state at the beginning, we need to find a value x such that
solving for x
So, we have to add just 2/7 ml of the stronger solution.
Answer:
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