This should be recognized as the difference of perfect squares which is of the form:
(a^2-b^2) and the difference of squares always factors to:
(a-b)(a+b) in this case:
(3x-8)(3x+8)
Answer:
28 different ways
Step-by-step explanation:
This is a combination question. Combination has to do with selection.
Total number of element in the set = 8
Number divisible by 6 or 8 are {-98, -48, -42, -36, -18, -6}
Total number divisible by 6 or 8 is 6
The number of ways we can choose 6 items from 8 is expressed as;
8C6 = 8!/(8-6)!6!
8C6 = 8!/(2)!6!
8C6 = 8*7*6!/2!6!
8C6 = 8*7/2
8C6 = 56/2
8C6 = 28 ways
Hence there are 28 different ways
Answer:
Step-by-step explanation:
1. There are only 4 numbers including 5 that follow the "five or more" requirment, and the probability of spinning it once is 4/8, or 1/2. (The total sections is 8) Then we multiply 1/2 and 1/2 together to get the "two times in a row" requirement done. (1/2)*(1/2)= 1/4 is the probability.
2. There are two values on the spinner that are a multiple of 3, 3 itself and 6. Again, the total amount of numbers/sections is 8, so the probability of spinning a multiple of three is 2/8 or 1/4. The probability of spinning an odd number is 4/8 or 1/2. (1/2)*(1/4)=1/8 is the probability.
3. The probability of spinning one odd number is 1/2, and so we multiply 1/2 by itself four times. (1/2)*(1/2)*(1/2)*(1/2)=1/16 is the probability.
4. There are 6 numbers greater than two on the number wheel not including two itself. So the probability of that is 6/8, or 3/4. Then we multiply 3/4 by itself 3 times as it asks. (3/4)*(3/4)*(3/4)*(3/4)=81/256 is the probability.
Note that I am not really sure about the answer myself, but I hope that this can help in some way. Good luck! :)
