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attashe74 [19]
3 years ago
11

So what's the answer for 35% of 22

Mathematics
2 answers:
kondor19780726 [428]3 years ago
8 0
You divide 22 by 10 (2.2) and then multiply that by 3 to get 30%, which is 6.6. Then, you divide 2.2 by 2 to get 1.1, which is 5%. After this you just add them up to get the answer as 7.7.
Also, if you have q calculator, you can do it the short way and do 22 × 0.35 = 7.7
natima [27]3 years ago
5 0
The answer is 7.7 Have a good night
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The answer is:  "4" .
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<u>Note</u>:  The question asks for a whole number.

"The area of the triangle above will equal one half of a rectangle that is 5 units long and <u>  4  </u><u /> units wide.  (Input only whole numbers, such as 8.).
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<u>Note</u>:  The diagram shows a "right triangle" ; which would be "one-half" of a rectangle, with units of "length" being "5 units" (as mentioned in this very question prompt;  and a width of "4" units (as shown in the diagram;  hence the answer is "4" units). 

Furthermore, the formula/equation for the area, "A" , of a triangle is: 


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As such, the answer, "4" (units) makes sense.
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3 years ago
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A Norman window has the shape of a rectangle surmounted by a semicircle. Suppose the outer perimeter of such a window must
Feliz [49]

The base length that will maximize the area for such a window is 168.03 cm. The exact largest value of x when this occurs is 233.39 cm

Suppose we make an assumption that:

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Also, provided that the diameter of the semi-circle appears to be the base of the rectangle, then;

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and, the perimeter of the window can now be expressed as:

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Given that the perimeter = 600 cm

∴

\mathbf{ \Big ( 1 + \dfrac{\pi}{2}\Big) x + 2h= 600}

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Since h > 0, then:

\mathbf{  h = 300 - \Big( \dfrac{1}{2} + \dfrac{\pi}{4}\Big) x>0}

By rearrangement and using the inverse rule:

\mathbf{  x<  \dfrac{ 300}{\Big( \dfrac{1}{2} + \dfrac{\pi}{4}\Big) } }

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\mathbf{  x=  233.39 \ cm }

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However, the area of the window is given as:

\mathbf{A(x) = xh + \dfrac{1}{2} \pi r^2}

\mathbf{A = x \Big [  300 - \Big ( \dfrac{1}{2}+\dfrac{1}{4} \Big) x \Big ]  +\dfrac{1}{2}\pi \Big(\dfrac{x}{2} \Big )^2}

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Now, at maximum, when the area A = 0. Taking the differentiation, we have:

\mathbf{\dfrac{d}{dx} 300x - \dfrac{d}{dx} \Big( \dfrac{1}{2} + \dfrac{\pi}{8}\Big) x^2 \ =0}

\mathbf{ 300 - 2x \Big( \dfrac{1}{2} + \dfrac{\pi}{8}\Big)  \ =0}

Making x the subject of the formula, we have:

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Taking the second derivative:

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\mathbf{= -2 \Big( \dfrac{1}{2}+\dfrac{\pi}{8}\Big )

Therefore, we can conclude that the maximum area that exists for such a window is 168.03 cm

Learn more about derivative here:

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Answer:

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4 years ago
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Happy to Help!

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