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SIZIF [17.4K]
3 years ago
8

Alegbra 4 questions giving brainlist!

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
3 0

Answer:

1) 4

2) 1

3) -7

4) 13

Step-by-step explanation:

Instructions:

a) Subtract or add the slope from each side

( it doesn't matter which one you pick )

b) Subtract or add the # next to the slope from each side

( it doesn't matter which one you pick )

c) Divide Each number by the slope

d You have you answer

____________________________________________

1) 9x - 35 = - 7x + 29

+7x + 7x

_____________________

16x - 35 = 29

+ 35 +35

_____________________

16x = 64

_____________________

16 16

x = 4

2). - 2x - 2 = 9x - 13

+2x +2x

_____________________

- 2 = 11x - 13

+ 13 + 13

_____________________

11 = 11x

_____________________

11 11

1 = x

3). 3x + 29 = - 5x - 27

+5x + 5x

_____________________

8x + 29 = - 27

-29 -29

_____________________

8x = -56

_____________________

8 8

x = -7

4). x - 11 = 3x - 37

- x - x

______________________

-11 = 2x - 37

+37 +37

______________________

26 = 2x

_______________________

2 2

13 = x

Hope this helps! (:

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If f(x) = x and g(x) = 2x + 7, what is<br>f[90X)] when g(x) = 11?​
kumpel [21]

\bf \begin{cases} f(x) = x\\ g(x) = 2x+7 \end{cases}~\hspace{7em}g(x)=11\implies \stackrel{g(x)}{11}=2x+7 \\\\\\ 4=2x\implies \cfrac{4}{2}=x\implies \implies \boxed{2=x} \\\\[-0.35em] ~\dotfill\\\\ f[90x]\implies f\left[90\left( \boxed{2} \right)\right]\implies f(180)=\stackrel{x}{180}

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=2%20%5Ctimes%202" id="TexFormula1" title="2 \times 2" alt="2 \times 2" align="absmiddle" class
Kruka [31]
The answer for this is 4
4 0
3 years ago
Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
4 years ago
90% of 11 is what number
umka2103 [35]
It would be: 11 * 90/100
= 11 * 0.90 = 9.9

So, your final answer is 9.9

Hope this helps!
8 0
4 years ago
Not understanding what to do need gelp
Natasha_Volkova [10]

Answer:

42

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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