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3 years ago

Please Please Please help

Mathematics

2 answers:

r-ruslan [8.4K]3 years ago

8 0

Answer:

it´s freaking 4

Step-by-step explanation:

MakcuM [25]3 years ago

6 0

Answer:

6,6

Step-by-step explanation:

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£65

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3 years ago

Divide the following quantiles in the given ratio £100 1:3 £80 3:5 £250 2:3:5

goblinko [34]

Answer:

Step-by-step explanation:

£100

1:3

1+3=4

1/4×£100

=£25

3/4×£100

=£75

£80

3:5

3+5=8

3/8×£80

=£30

5/8×£80

=£50

£250

2:3:5

2+3+5=10

2/10×£250

=£50

3/10×£250

=£75

5/10×£250

=£125

6 0

3 years ago

Plz help me with this

AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$