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melisa1 [442]
3 years ago
11

Write an equation for the relationship shown on this graph if the price per ticket is doubled.​

Mathematics
1 answer:
vlabodo [156]3 years ago
8 0

Answer:

y = 2x

linear equations are just finding the right ratio and putting it in y = mx+b format

this graph is saying that two dollars are earned for every ticket sold, a 2:1 ratio.

so the equation would be y = 2x, two being the amount of money collected for one ticket, and x being the number of tickets sold.

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Simplify √18<br><br><br> A. 2√3<br> B. 2√9<br> C. 3√2<br> D. 9√2
fiasKO [112]
C

Explanation: Rewrite 18 as 3^2 * 2

REASON: Factor 9 out of 18
Rewrite 9 as 3^2


Pull terms out from under the radical

Answer: 3√2
5 0
3 years ago
Water is added or drained from a tank each day. The first day, 910 of a gallon is added to the empty tank. The second day, 710 o
dimulka [17.4K]

Answer:

The quantity of water in the tank after 15 days is 1610.0 gallons OR 1.61 × 10³ gallons.

Step-by-step explanation:

The amount of water in the tank after 15 days is given by the series

910+(−710)+810+(−610)+⋯+310+(−110)+210

From the series, we can observe that, if water is added for a particular day then water will be drained the following day.

Also, for a day when water is to be added, the quantity to be added will be 100 gallon lesser than the quantity that was last added. Likewise, for a day when water is to be drained, the quantity to be drained will be 100 gallons lesser than the quantity that was last drained.

Hence, we can complete the series thus:

910+(−710)+810+(−610)+710(-510)+610(-410)+510(-310)+410(-210)+310+(−110)+210

To evaluate this, we  get

910-710+810-610+710-510+610-410+510-310+410-210+310-110+210

= 1610.0 gallons

Hence, the quantity of water in the tank after 15 days is 1610 gallons OR 1.61 × 10³ gallons.

8 0
3 years ago
Can someone help me ASAP!!
Lana71 [14]

The answer is 5.

Step-by-step explanation:

To find the interquartile range you must look at the median and the upper and lower halves of the data. The median (12) to the upper half of the data (15) is 3. Next, look at the median (12) to the lower half of the data (10) it is 2. We then add 2 and 3 to get the interquartile range of 5.

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3 years ago
(3.2 x 10^14) (5.1 x 10^2) in scientific notation
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3 years ago
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