a ball is thrown into the air. After t seconds, the ball's height is given by h(t)+=12-3(t-2) squared where h is measured in fee
t. What is the maximum height of the ball?
2 answers:
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Answer:
The interval [32.6 cm, 45.8 cm]
Step-by-step explanation:
According with the <em>68–95–99.7 rule for the Normal distribution:</em> If is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval
around 95% of the data must fall in the interval
around 99.7% of the data must fall in the interval
So, the range of lengths that covers almost all the data (99.7%) is the interval
[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]
<em>This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%</em>