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3 years ago

What is the solution to the system of linear equations? 2x+4y=38 10x+3y=105

2 answers:

6 0

Hello :
<span>2x+4y=38 ...(1)
10x+3y=105....(2)
-10x-20y = - 190
10x+3y =105
add : -17y = - 85
y = 5
subsct in (1) : 2x +20 =38
2x = 18
x=9

</span>

Mumz [18]3 years ago

5 0

Answer: The required solution is (x, y) = (9, 5).

Step-by-step explanation: We are given to find the solution of the following system of linear equations :

$2x+4y=38~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\10x+3y=105~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Multiplying equation (i) by 5, we have

$5(2x+4y)=5\times38\\\\\Rightarrow 10x+20y=190~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Subtracting equation (ii) from equation (iii), we get

$(10x+20y)-(10x+3y)=190-105\\\\\Rightarrow 17y=85\\\\\Rightarrow y=\dfrac{85}{17}\\\\\Rightarrow y=5.$

Substituting the value of y in equation (i), we get

$2x+4\times5=38\\\\\Rightarrow 2x+20=38\\\\\Rightarrow 2x=38-20\\\\\Rightarrow 2x=18\\\\\Rightarrow x=\dfrac{18}{2}\\\\\Rightarrow x=9.$

Thus, the required solution is (x, y) = (9, 5).

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You have a coin that is not weighted evenly and therefore is not a fair coin. Assume the true probability of getting heads when

Alexandra [31]

Answer:

$X \sim Binom(n=157, p=0.52)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X$

And we can use the following Excel code to find the exact answer:

"=BINOM.DIST(75,157,0.52,TRUE)"

And we got 0.1633

The other way to solve the problem is using the normal approximation

We need to check the conditions in order to use the normal approximation.

$np=157*0.52=81.64 \geq 10$

$n(1-p)=157*(1-0.52)=75.36 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=157*0.52=81.64$

$\sigma=\sqrt{np(1-p)}=\sqrt{157*0.52(1-0.52)}=6.26$

We want this probability:

$P(X$

And using the continuity correction we have this:

$P(X$

We can use the z score given by this formula $Z=\frac{x-\mu}{\sigma}$ .

$P(X< 76.5)=P(\frac{X-\mu}{\sigma}< \frac{76.5-81.64}{6.26})=P(Z < -0.821)=0.206$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=157, p=0.52)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X$

And we can use the following Excel code to find the exact answer:

"=BINOM.DIST(75,157,0.52,TRUE)"

And we got 0.1633

The other way to solve the problem is using the normal approximation

We need to check the conditions in order to use the normal approximation.

$np=157*0.52=81.64 \geq 10$

$n(1-p)=157*(1-0.52)=75.36 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=157*0.52=81.64$

$\sigma=\sqrt{np(1-p)}=\sqrt{157*0.52(1-0.52)}=6.26$

We want this probability:

$P(X$

And using the continuity correction we have this:

$P(X$

We can use the z score given by this formula $Z=\frac{x-\mu}{\sigma}$ .

$P(X< 76.5)=P(\frac{X-\mu}{\sigma}< \frac{76.5-81.64}{6.26})=P(Z < -0.821)=0.206$

4 0

3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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1. No Solution

2. One solution

3. Infinitely many solutions

3 0

3 years ago