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9966 [12]
3 years ago
8

In captivity, the average life span of a grizzly bear is 9 years more than that of a tiger. The sum of the two average life span

s is 41 years. Find the average life span of a tiger in captivity.
Mathematics
1 answer:
zaharov [31]3 years ago
4 0
It would be 25 years if you need to know how I got this just ask
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Consider the diagram to the right below and complete the proof below
kiruha [24]
I don’t know about this question
8 0
3 years ago
Some body can help me with a geometric mean maze
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

Theorem 1: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

Theorem 2: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

1. Start point: By the 1st theorem,

x^2=25\cdot (49-25)=25\cdot 24=5^2\cdot 2^2\cdot 6\Rightarrow x=5\cdot 2\cdot \sqrt{6}=10\sqrt{6}.

2. South-East point from the Start: By the 2nd theorem,

x^2=40\cdot (40+5)=4\cdot 5\cdot 2\cdot 9\cdot 5\Rightarrow x=2\cdot 5\cdot 3\cdot \sqrt{2}=30\sqrt{2}.

3. West point from the previous: By the 2nd theorem,

x^2=(32-20)\cdot 32=4\cdot 3\cdot 16\cdot 2\Rightarrow x=2\cdot 4\cdot \sqrt{6}=8\sqrt{6}.

4. West point from the previous: By the 1st theorem,

9^2=x\cdot 15\Rightarrow x=\dfrac{81}{15}=\dfrac{27}{5}=5.4.

5. West point from the previous: By the 2nd theorem,

10^2=8\cdot (8+x)\Rightarrow 8+x=12.5,\ x=4.5.

6. North point from the previous: By the 1st theorem,

x^2=48\cdot 6=6\cdot 4\cdot 2\cdot 6\Rightarrow x=6\cdot 2\cdot \sqrt{2}=12\sqrt{2}.

7. East point from the previous: By the 2nd theorem,

x^2=22.5\cdot 30=225\cdot 3\Rightarrow x=15\sqrt{3}.

8. North point from the previous: By the 1st theorem,

x^2=7.5\cdot 36=270\Rightarrow x=3\sqrt{30}.

8. West point from the previous: By the 2nd theorem,

x^2=12.5\cdot (12.5+13.5)=12.5\cdot 26=25\cdot 13\Rightarrow x=5\sqrt{13}.

9. North point from the previous: By the 1st theorem,

12^2=x\cdot 30\Rightarrow x=\dfrac{144}{30}=4.8.

101. East point from the previous: By the 1st theorem,

6^2=1.6\cdot (x-1.6)\Rightarrow x-1.6=22.5,\ x=24.1.

11. East point from the previous: By the 2nd theorem,

20^2=32\cdot (32-x)\Rightarrow 32-x=12.5,\ x=19.5.

12. South-east point from the previous: By the 2nd theorem,

18^2=x\cdot 21.6\Rightarrow x=15.

13. North point=The end.

6 0
3 years ago
Given: AC and AE are common external tangents of G and D. BC= 123 GB=20 and AG=101. What is the measure of AC?​
Solnce55 [7]

Answer:

The length of AC is 222 units.

Step-by-step explanation:

Given AC and AE are common external tangents of G and D.

BC= 123 ,  GB=20 and AG=101.

We have to find the measure of AC.

As, a straight line joined from the center i.e radius is perpendicular to tangent drawn. Therefore,

In ΔABG, by Pythagoras theorem

AG^2=AB^2+BG^2

⇒ 101^2=AB^2+20^2

⇒ AB^2=10201-400=9801

⇒ AB=99 units.

Hence, AC=AB+BC=99+123=222 units.

The length of AC is 222 units.

8 0
3 years ago
7x(x²-x+5) Multiply.
Sloan [31]

Answer:

7x^3 - 7x^2 + 35x

Step-by-step explanation:

7x(x^2-x+5)

7x^3-7x^2+35x

6 0
3 years ago
-2(-8) please help me
olya-2409 [2.1K]

Answer:

Its 7 hope i helped

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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