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timofeeve [1]
3 years ago
8

Kari thinks, "x is the difference between 87 and 34.25 is this true or not?

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
4 0
This is true because it is an unknown number so it is replaced by a variable.
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In a class of 30 students, 12 are girls. What percent of the class is girls
dexar [7]

Answer:

40%

Step-by-step explanation:

Total students = 30

No. of girls. = 12

Girls % = ?

Girls % = No. of girls/Total students * 100%

= 0.4 * 100

= 40%

5 0
3 years ago
What is the factorization???
Sav [38]

we can see that

the above curve is parabola

so, firstly , we can find vertex

vertex is (4,0)

(h,k)=(4,0)

now, we can use vertex formula of parabola

y=(x-h)^2+k

we can plug h and k

and we get

y=(x-4)^2+0

so, we can factor it as

y=(x-4)(x-4)............Answer

6 0
3 years ago
If mn, solve for x.<br> (3x + 9) (x + 21)
Sloan [31]

2

3x. + 63x + 9x + 189

Step-by-step explanation:

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6 0
3 years ago
Can y’all help me understand this
Natasha2012 [34]

Answer:

Yo teachers doing you wrong with this cryptic stuff

Step-by-step explanation:

8 0
3 years ago
The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 330 grams and a standard deviati
just olya [345]

Answer:

Weights of at least 340.1 are in the highest 20%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 330, \sigma = 12

a. Highest 20 percent

At least X

100-20 = 80

So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.

Z = \frac{X - \mu}{\sigma}

0.842 = \frac{X - 330}{12}

X - 330 = 12*0.842

X = 340.1

Weights of at least 340.1 are in the highest 20%.

3 0
3 years ago
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