Kari thinks, "x is the difference between 87 and 34.25 is this true or not?

In a class library, 3 out of 4 books are non-fiction. The rest are fiction.

denis23 [38]

Are you looking for specific answers? What are your options?

4 0

3 years ago

If you have the option of choosing a loan that will accumulate 4%/ a interest compounded semi-annually compared to a loan that w

alexira [117]

Answer:

4%/ a interest compounded semi-annually

Step-by-step explanation:

The option that gives the lower interest rate payment would be more appropriate. to determine this calculate the effective interest rate

Effective annual rate = (1 + APR / m ) ^m - 1

M = number of compounding

(1 + 0.04/2)^2 - 1 = 4.04%

(1 + 0.04/12)^12 - 1 = 4.07%

the choice should be 4%/ a interest compounded semi-annually

6 0

3 years ago

According to records, the amount of precipitation in a certain city on a November day has a mean of inches, with a standard devi

Mekhanik [1.2K]

Answer:

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is mean amount of inches of rain and $\sigma$ is the standard deviation.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean $\mu$ , standard deviation $\sigma$

n days:

This means that $s = \frac{\sigma}{\sqrt{n}}$

Applying the Central Limit Theorem to the z-score formula.

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

What is the probability that the mean daily precipitation will be of X inches or less for a random sample of November days?

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is mean amount of inches of rain and $\sigma$ is the standard deviation.

5 0

3 years ago

1.6y + y - 4/15 y + 1 1/6y = 2 1/3 Please help!

Yuri [45]

Answer:

y = 2/7 or y = 14/25

Step by Step explanation:

sorry about the last answer

simplify both sides of the equation, then isolate the variable

8 0

3 years ago

Read 2 more answers

Which role would result in a translation of two units left and three units up

VladimirAG [237]

The rule (x, y) ⇒ (x-2, y+3) will translate the way you want.

7 0

3 years ago