How many attempts are you allowed?
try A'(2,5), B'(4,5), C'(4,4) and D'(2,2)
(c): A'(4,3), B'(6, 3), C'(6,2) and D'(4,0)
this is the best I can do.
The probability that a person wins the game is 32.1%
<h3>How to illustrate the probability?</h3>
Based on the information given, the following can be depicted. It should be noted that there are 6 sides as well as 4 cards.
Therefore, the numbers on the dice i.e from 1 - 6 will be represented 4 times each. This gives a total of (4 × 6) = 24. There are also 4 cards. The total in sample space will now be:
= 24 + 4 = 28
The frequency table will be such that 28 or more have a relative frequency of 9. Therefore, the probability that a person wins the game will be:
= 9/28 = 32.1%
When you win 25% of the time, this illustrates that the number of products picked will be:
= 25% × 28
= 7 products.
The probability of participants achieving a winning score of 36 or higher in four consecutive attempts will be:
= 1/6⁴ = 1/1296
Learn more about probability on:
brainly.com/question/24756209
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<span>product of the second and third integer is 63
63=3*3*7
or
63=7*9 These are two consecutive integers.
We need three integers and the first one is missing so the solution:
5-7-9
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B. No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32
Perimeter = 2(l + w)
Perimeter = 64
Assuming: P = 64; w = 11 ; l = ?
64 = 2(l + 11)
64/2 = l + 11
32 - 11 = l
length = 21.
<span> i'm going to be slightly extra careful in showing each step. specific, ln [n / (n+a million) ]= ln n - ln(n+a million). So, we've sum(n=a million to infinity) ln [n / (n+a million) ] = lim(ok--> infinity) sum(n=a million to ok) ln [n / (n+a million) ] = lim(ok--> infinity) sum(n=a million to ok) [ln n - ln(n+a million)] = lim(ok--> infinity) (ln a million - ln 2) + (ln 2 - ln 3) + ... + (ln ok - ln(ok+a million)) = lim(ok--> infinity) (ln a million - ln(ok+a million)), for the reason that fairly much all the words cancel one yet another. Now, ln a million = 0 and lim(ok--> infinity) ln(ok+a million) is countless. So, the sum diverges to -infinity. IM NOT COMPLETELY SURE
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