Answer:
x = -6.5, x = 8.5
Step-by-step explanation:
The given equation ...
x^2 -4x -31 = -2x +25
can be rewritten to a form that facilitates completing the square:
x^2 -2x = 56 . . . . . add 2x+31
x^2 -2x +1 = 57 . . . add 1 to complete the square
(x -1)^2 = 57 . . . . . write the left side as a square
x -1 = ±√57 . . . . . take the square root
x = 1 ±√57 ≈ {-6.5, 8.5} . . . . . add 1, evaluate
Solutions are near x = -6.5 and x = 8.5.
Answer:
n¹³
Step-by-step explanation:
Division and multiplication have the same priority in pemdas, so you can solve this by dividing/multiplying from left to right.
Also remember that when dividing exponents of the same base, you subtract them, and when multiplying, you add them.
n⁶· n⁵ · n⁴ ÷ n³ · n² ÷ n
= (n⁶· n⁵) · n⁴ ÷ n³ · n² ÷ n
= (n¹¹ · n⁴) ÷ n³ · n² ÷ n
= (n¹⁵ ÷ n³) · n² ÷ n
= (n¹² · n²) ÷ n
= n¹⁴ ÷ n
= n¹³
Ultimately you just have to calculate
6 + 5 + 4 - 3 + 2 - 1 = 13
The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma()
E(X)=
=
=6 weeks
V(x)=
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X, ,
, False)
P()
P()
P()
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
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