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solong [7]
3 years ago
14

Simplify 3sqrt -32 x^4 y^6

Mathematics
1 answer:
Tju [1.3M]3 years ago
5 0
3 sqrt(-32) x^4 y^6
sqrt(-32) = sqrt(-1) sqrt(32) = i sqrt(32):
3 i sqrt(32) x^4 y^6
sqrt(32) = sqrt(2^5) = 2^2 sqrt(2):
3 i×2^2 sqrt(2) x^4 y^6
2^2 = 4:
3 i×4 sqrt(2) x^4 y^6
3×4 = 12:
Answer:  12 i sqrt(2) x^4 y^6
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Step-by-step explanation:

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3 years ago
Solve -1 < x + 1 ≤ 6
andrey2020 [161]

Answer:

-2<x≤5

Step-by-step :

-1<x+1≤6 So fisrt what every we do to one side we must do to the other. In this case it's a bit different since we are dealing with inequalities.

-1<x+1≤6 I would start off by isolating x in the middle.

-1<x+1≤6 I subtracted 1 from all three sides.

-1     -1   -1

Now your equation should look like this:

-2<x≤5  Now there is really nothing much we can do here since we were just trying to get x by its self.

Answer : -2<x≤5

7 0
3 years ago
A woman saw oranges and mangos ad the market. She bought some oranges at 35 cents each and some mangoes at $1.00. if she bought
marysya [2.9K]

Answer: 20 oranges and 5 mangoes

Step-by-step explanation:

Define the following:

x = number of oranges

y = number of mangoes

Make the following system of equations:

x + y = 25

0.35x + 1.00y = 12.00

Solve for x:

y = 25 - x

⇒ 0.35x + 1.00(25 - x) = 12.00

⇒ 0.35x + 25 - x = 12.00

⇒ -0.65x = -13.00

⇒ x = 20

Solve for y:

20 + y = 25

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2 years ago
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Step-by-step explanation:

6 0
3 years ago
A sequence is constructed according to the following rule: its first term is 7, and each next term is one more than the sum of t
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Answer:

5

Step-by-step explanation:

According to the described rule, we have

a_1=7\\ \\a_1^2=7^2=49\Rightarrow a_2=4+9+1=14\\ \\a_2^2=14^2=196\Rightarrow a_3=1+9+6+1=17\\ \\a_3^2=17^2=289\Rightarrow a_4=2+8+9+1=20\\ \\a_4^2=20^2=400\Rightarrow a_5=4+0+0+1=5\\ \\a_5^2=5^2=25\Rightarrow a_6=2+5+1=8\\ \\a_6^2=8^2=64\Rightarrow a_7=6+4+1=11\\ \\a_7^2=11^2=121\Rightarrow a_8=1+2+1+1=5\\ \\\text{and so on...}

We can see the pattern

a_5=a_8=a_{11}=a_{14}=...=5\\ \\a_6=a_9=a_{12}=a_{15}=...=8\\ \\a_7=a_{10}=a_{13}=a_{16}=...=11

In other words, for all k\ge 2

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Now,

a_{2018}=a_{3\cdot 673-1}=5

7 0
4 years ago
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