PLEASEEE HELPPPPPPP!! please explain
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Answer:
77.38% probability that the mean length of the sample rods would differ from the population mean by less than 0.7 millimeters
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central limit theorem:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation
, the sample means with size n of at least 30 can be approximated to a normal distribution with mean
and standard deviation
In this problem, we have that:
If 299 rods are sampled at random from the batch, what is the probability that the mean length of the sample rods would differ from the population mean by less than 0.7 millimeters
This is the pvalue of Z when X = 170 + 0.7 = 170.7 subtracted by the pvalue of Z when X = 170 - 0.7 = 169.3. So
X = 170.7
By the Central Limit Theorem
has a pvalue of 0.8869
X = 169.3
has a pvalue of 0.1131
0.8869 - 0.1131 = 0.7738
77.38% probability that the mean length of the sample rods would differ from the population mean by less than 0.7 millimeters