Answer:
The percentage of the population that is heterozygous for this trait is 48%
Explanation:
They are two alleles, the phenylthiocarbamide tasters (PTC) and the non phenylthiocarbamide tasters (non PTC). PTC testers are dominant and non PTC tasters are recessive.
let the frequency of the dominant allele(A) be p
and the frequency of the recessive allele(a) be q
We are told that 64 percent of people living in a remote, isolated mountain village can taste phenylthiocarbamide (PTC) and must, therefore, have at least one copy of the dominant PTC taster allele (that is AA and Aa)
Frequency of AA = p², Frequency of Aa = 2pq and Frequency of aa = q²
Therefore p² + 2pq = 64% = 0.64
According to Hardy–Weinberg:
p² + 2pq + q² = 1 and
p + q = 1
Since p² + 2pq = 0.64
∴ 0.64 + q² = 1
q² = 1 - 0.64 = 0.36
q = √0.36 = 0.6
Since p + q = 1
p = 1 - q = 1 - 0.6 = 0.4
The frequency of heterozygous = 2pq = 2 × 0.4 × 0.6 = 0.48
Therefore the percentage of the population that is heterozygous for this trait is 48%
Answer:
Organisms depend on other members of an ecosystem to live and grow. For example, in a symbiosis, buffalo birds will lay eggs in the nest of other birds. These chicks then depend on the parent birds to raise them.
Explanation:
The answer would b a so the top person is correct:))
Answer:
B. Brown Hair is dominant.
Explanation:
The dominant allele is represented with a capital letter, and a recessive allele is represented with a lower case letter.
Therefore, In this example brown hair is dominant. :)
There would be a decrease in formation of NADPH, that is used in the Calvin cycle.
