Answer:
f^-1 (x) = 1+ln( (x-3)/2)
Step-by-step explanation:
hello :
let f(x) = y so : y = 2e^(x-1) +3
calculate x : e^(x-1) = (y-3)/2
for : y-3 > 0 : x-1 = ln( (y-3)/2) so : x= 1+ln( (y-3)/2)
If(x)= 2e^(x-1) +3 , what is f^-1 (x) = 1+ln( (x-3)/2)
Let Q= the number of quarters and D= the number of dimes.
Q+D= 40 coins
0.25Q+0.1D= $7.75
Rewrite equation 1 as: D = 40-Q and substitute into equation 2
0.25Q+0.1(40-Q)= 7.75 Simplify the left side
0.25Q+4-0.1Q= 7.75 Subtract 4 from both sides
0.25Q-0.1Q= 3.75 Convime like terms on left side
0.15Q= 7.75 Divide both sides by 0.15
Q=25 and D= 40-Q
D= 40-25 which is 15
So Jenna had 25 quarters and 15 dimes.
<span>To check multiply 25 x 25 and 15x10 which equals 625 and 150 this equals 775 so this is 7.75</span>
Answer:
it would be 28y minus 3
Step-by-step explanation:
Answer:
The distance between the points is 9.219544457292887
Step-by-step explanation:
