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Verdich [7]
3 years ago
14

Question about dilation attached in images.

Mathematics
1 answer:
statuscvo [17]3 years ago
5 0
This is an enlarged dilation
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when you sign up for video games are you get 400 points you earn 50 more points for each hour that you play how many hours do yo
aleksandr82 [10.1K]
This is a linear equation
y=mx+b
y=50x+400 (when x equals the number of hours played)

1000=50x+400
*first, isolate the variable (x)
-50x=-1000+400
*divide by -50 to get x by itself
x=20+8

The answer is x=28
4 0
3 years ago
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Makayla is working two summer jobs, making $19 per hour tutoring and making $12 per hour landscaping. In a given week, she can w
Ivanshal [37]

Answer: 12 hours

Step-by-step explanation:

3 hours landscaping = $36

She still needs to make $224 to meet her requirement.

$224 divided by $19 tutoring = 11.79 hours

224÷19=11.79

Rounded to the nearest whole number: 12

This would mean Makayla worked a total of 15 hours and made $264. Which meets her requirements.

8 0
3 years ago
Please answer this correctly
Crank

Answer:

Its absolutely cone , it has one triangle face seen from front , and a circular base

8 0
3 years ago
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Which statement below is correct​
Lynna [10]
The correct answer is A
4 0
3 years ago
A fighter tank targets an enemy helicopter flying at an altitude of 1250 ft. If the ground
madam [21]

By using trigonometric relations, we will see that the angle of elevation must be 55°.

<h3>How to find the angle of elevation?</h3>

We can see this as a right triangle, where one cathetus measures 1250ft (altitude) and the other cathetus measures 875ft.

The angle of elevation is the angle such that the adjacent cathetus is the one measuring 875ft.

Then we can use the relation:

tan(a) = (opposite cathetus)/(adjacent cathetus)

tan(a) = 1250ft/875ft

To find the angle of elevation, we can use the inverse tangent function:

a = Atan(1250ft/875ft) = 55°

The angle of elevation must be 55 degrees.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

7 0
1 year ago
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