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musickatia [10]
3 years ago
7

So I copied this off from my teacher she was showing this on the board but I need help showing my work on this so that she doesn

’t know I copied it which I think she wouldn’t but you never know

Mathematics
2 answers:
IRISSAK [1]3 years ago
6 0

Answer:

x < 3 or x > 9

Step-by-step explanation:

given 6| x - 6 | + 7 > 25 ( subtract 7 from both sides )

6| x - 6 | > 18 ( divide both sides by 6 )

| x - 6 | > 3

Inequalities of the form | x | > a always have solutions of the form

x < - a OR x > a, hence

x - 6 < - 3 or x - 6 > 3 ( add 6 to both sides in both inequalities )

x < 3 or x > 9


kaheart [24]3 years ago
5 0

Answer: x > 9 or x < 3

<u>Step-by-step explanation:</u>

Step 1: Isolate the absolute value expression.

6 | x - 6 | + 7 > 25

6 | x - 6 |  > 18      <em>subtracted 7 from both sides</em>

   | x - 6 |  > 3        <em>divided both sides by 3</em>


Step 2: Solve for x.

Note: the absolute value symbol makes the value positive, so the value inside could be positive or negative. We need to find both solutions.

<u>If inside is negative</u>

-(x - 6) > 3

 x - 6 < -3      <em>divided both sides by -1 which flipped the inequality</em>

     x < 3        <em>added 6 to both sides</em>


<u>If inside is positive</u>

+(x - 6) > 3

 x - 6 > 3      <em>distributed +1, which didn't change the inequality</em>

     x > 9        <em>added 6 to both sides</em>


Step 3: Graph the solution

←-------------o -3           9 o--------------→

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\huge\text{Hey there!}


\huge\textsf{Breaking the meaning down in simpler terms}
\huge\textbf{Median:}\\\large\text{is understood to be \bf the number in the center (also known as}\\\large\textbf{the middle number)}


\huge\textbf{Mean:}\\\large\text{is understood to be the \bf total.}

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\huge\textsf{Median:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textbf{Conversion: }\large\text{27, 33, 38, 41, 42, 52, 64, 68, 72}\\\\\large\textsf{Make sure it is even between both sides of the data plot.}\\\\\large\text{It seems to even on BOTH sides of  \boxed{\textsf{14}} so it could possibly be your}\\\large\text{median.}

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\huge\text{Good luck on your assignment \& enjoy your day!}

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