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IRISSAK [1]
3 years ago
6

Austin is raising money for a school trip by selling fruit snacks and candy bars. The price of each fruit snack is $1 and the pr

ice of each candy bar is $2. Yesterday Austin made $32 and he sold twice as many fruit snacks as candy bars. Determine the number of fruit snacks sold and the number of candy bars sold.
Mathematics
1 answer:
julia-pushkina [17]3 years ago
6 0
16 fruit snacks and 8 candy bars
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Samantha has $24 but she wants a pair of Jordan's that are $112. She does chores and she gets paid $5 for each chore. If she doe
natita [175]

Answer:

Check step-by-step.

Step-by-step explanation:

Okay, so. She gets 5 dollars and she does 15 chores. You would multiply it.

5 * 15 = $75

Then you would subtract 112 and 75.

112 - 75 = 37.

She will get $75. Then, she will need to gather $37

6 0
3 years ago
I wish to digitally store a very old book written in an ancient Chinese language. What is the minimum number of megabytes (to th
Alisiya [41]

Answer:

The total number number of megabytes required to store the book is

Step-by-step explanation:

The smallest unit of storage on a computer  are Bits. That is, a single on/off value.

This is different from a Bytes.

Bytes are often represented by the capital letter B, bits by a lower case b.

Please note: A single typed character (for example, 'x' or '8') is stored in one byte.

1 Byte = 8 bits.

1, 000 Bytes = 1 Kilobyte and

1,024 Kilobytes = 1 Megabyte

Therefore 1,000,000 Bytes = 1 Megabyte

STEP I - Get the Number of Bytes required.

Each symbol = 1 byte

Each Page has 445.8 symbols

The book has 360 pages.

Therefore, total number of symbols =

445.8 x 360

= 160, 488 Bytes

If our answer has to be in Megabytes, recall that 1,000,000 Bytes = 1 Megabyte.

Therefore the minimum number of megabytes required to store the book =

160,400/1,000,000

= 0.1604

In three decimal places our answer therefore is

= 0.160 Megabytes or 0.160MB.

Cheers!

8 0
3 years ago
Plz help me 25 pointssss!!!!!! Thxx <3
satela [25.4K]

Answer:

how should I help you with

7 0
3 years ago
Read 2 more answers
Perform the following operations s and prove closure. Show your work.
nadezda [96]

Answer:

1. \frac{x}{x+3}+\frac{x+2}{x+5} = \frac{2x^2+10x+6}{(x+3)(x+5)}\\

2. \frac{x+4}{x^2+5x+6}*\frac{x+3}{x^2-16} = \frac{1}{(x+2)(x-4)}

3. \frac{2}{x^2-9}-\frac{3x}{x^2-5x+6} = \frac{-3x^2-7x-4}{(x+3)(x-3)(x-2)}

4. \frac{x+4}{x^2-5x+6}\div\frac{x^2-16}{x+3} = \frac{1}{(x-2)(x-4)}

Step-by-step explanation:

1. \frac{x}{x+3}+\frac{x+2}{x+5}

Taking LCM of (x+3) and (x+5) which is: (x+3)(x+5)

=\frac{x(x+5)+(x+2)(x+3)}{(x+3)(x+5)}\\=\frac{x^2+5x+(x)(x+3)+2(x+3)}{(x+3)(x+5)} \\=\frac{x^2+5x+x^2+3x+2x+6}{(x+3)(x+5)} \\=\frac{x^2+x^2+5x+3x+2x+6}{(x+3)(x+5)} \\=\frac{2x^2+10x+6}{(x+3)(x+5)}\\

Prove closure: The value of x≠-3 and x≠-5 because if there values are -3 and -5 then the denominator will be zero.

2. \frac{x+4}{x^2+5x+6}*\frac{x+3}{x^2-16}

Factors of x^2-16 = (x)^2 -(4)^2 = (x-4)(x+4)

Factors of x^2+5x+6 = x^2+3x+2x+6 = x(x+3)+2(x+3) =(x+2)(x+3)

Putting factors

=\frac{x+4}{(x+3)(x+2)}*\frac{x+3}{(x-4)(x+4)}\\\\=\frac{1}{(x+2)(x-4)}

Prove closure: The value of x≠-2 and x≠4 because if there values are -2 and 4 then the denominator will be zero.

3. \frac{2}{x^2-9}-\frac{3x}{x^2-5x+6}

Factors of x^2-9 = (x)^2-(3)^2 = (x-3)(x+3)

Factors of x^2-5x+6 = x^2-2x-3x+6 = x(x-2)+3(x-2) =(x-2)(x+3)

Putting factors

\frac{2}{(x+3)(x-3)}-\frac{3x}{(x+3)(x-2)}

Taking LCM of (x-3)(x+3) and (x-2)(x+3) we get (x-3)(x+3)(x-2)

\frac{2(x-2)-3x(x+3)(x-3)}{(x+3)(x-3)(x-2)}

=\frac{2(x-2)-3x(x+3)}{(x+3)(x-3)(x-2)}\\=\frac{2x-4-3x^2-9x}{(x+3)(x-3)(x-2)}\\=\frac{-3x^2-9x+2x-4}{(x+3)(x-3)(x-2)}\\=\frac{-3x^2-7x-4}{(x+3)(x-3)(x-2)}

Prove closure: The value of x≠3 and x≠-3 and x≠2 because if there values are -3,3 and 2 then the denominator will be zero.

4. \frac{x+4}{x^2-5x+6}\div\frac{x^2-16}{x+3}

Factors of x^2-5x+6 = x^2-3x-2x+6 = x(x-3)-2(x-3) = (x-2)(x-3)

Factors of x^2-16 = (x)^2 -(4)^2 = (x-4)(x+4)

\frac{x+4}{(x-2)(x+3)}\div\frac{(x-4)(x+4)}{x+3}

Converting ÷ sign into multiplication we will take reciprocal of the second term

=\frac{x+4}{(x-2)(x+3)}*\frac{x+3}{(x-4)(x+4)}\\=\frac{1}{(x-2)(x-4)}

Prove Closure: The value of x≠2 and x≠4 because if there values are 2 and 4 then the denominator will be zero.

5 0
3 years ago
What is the polynomial function in standard form of f(x)=2-11x 2x²
vlabodo [156]
Standard form is f(x)=ax^2+bx+c
order of power
f(x)=2x^2-11x+2
4 0
3 years ago
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