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Masteriza [31]
3 years ago
8

Solve the following system of equations: x + 3y = −4 x + 5y = −6 pls and thx

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0

Answer:

work is pictured and shown

Agata [3.3K]3 years ago
4 0

Answer:

x = -1  y = -1

Step-by-step explanation:

x + 3y = −4

x + 5y = −6

Multiply the first equation by -1

-x - 3y = 4

The add to the second equation to eliminate x

-x - 3y = 4

x + 5y = −6

--------------------

 2y = -2

Divide by 2

2y/2 = -2/2

y = -1

Now solve for x

x+3y = -4

x +3(-1) = -4

x -3 = -4

Add 3 to each side

x-3+3 = -4+3

x = -1

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Divide -2x^3-5x^2+4x+2 by x+2
erik [133]

<u>Answer</u><u>: </u>

The correct option is C.  -2x^2-x+6, R(-10)

<u> Explanation: </u>

<u>Given:</u>

Dividend = -2x^3-5x^2+4x+2

Divider =(x+2)

<u>Solution</u>:

Now by using the division method , we will find out the quotient and remainder of the given equation  

And the equation will become  

-2x^3-5x^2+4x+2=(x+2)(-2x^2-x+6)-10

So , We will get the quotient =-2x^2-x+6

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4 0
3 years ago
In the year 1987, an investment was worth $29,800. In the year 1997, this
Veseljchak [2.6K]

Answer:

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In year 1997, investment worth $43800

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Rate of change = 43800 - 29800/29800 × 100

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