1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inessss [21]
3 years ago
12

Write an equation of a parabola that passes through the point (2,4) with vertex (-1,-1) in vertex form.

Mathematics
1 answer:
quester [9]3 years ago
8 0
An applicable equation of a vertical parabola in vertex form is:

y-k = a(x-h)^2

Let x=2, y=4, h=-1 and k=-1, where (h,k) is the vertex.  Then,

4-(-1) = a(2-[-1])^2, which becomes 5 = a(9).  Therefore, a = 5/9, and the 
equation of the parabola is

y+1 = (5/9)(x+1)
You might be interested in
Solve the inequality 2x – 5 > 7
ziro4ka [17]
<span>2x – 5 > 7 
Add 5 to both sides
2x > 12
Divide 2 on both sides
Final Answer: x > 6</span>
7 0
3 years ago
Determine if the table shows a linear or an exponential function​
____ [38]

Answer:

<em>The table shows an exponential function</em>

Step-by-step explanation:

<u>Linear vs Exponential Functions</u>

A linear function is written as:

y=mx+b

where m and b are constants.

If a table contains a linear function, then for each pair of ordered pairs (x1,y1) and (x2,y2), the value of m must be constant.

The slope can be calculated as:

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

An exponential function is written as:

y=y_o.r^x

Where r is the ratio and yo is a constant.

If a table contains an exponential function, for two ordered pairs (x1,y1) and (x2,y2), the value of r must be constant.

The ratio can be calculated as:

\displaystyle r=\sqrt[x2-x1]{\frac{y2}{y1}}

Calculate the slope for (0,4) and (1,2):

\displaystyle m=\frac{2-4}{1-0}=-2

Calculate the slope for (1,2) and (2,1):

\displaystyle m=\frac{1-2}{2-1}=-1

Since the slope is not the same, the function is not linear.

Now calculate the ratio for (0,4) and (1,2)

\displaystyle r=\sqrt[1-0]{\frac{1}{2}}

The radical of index 1 is simply equal to its argument:

\displaystyle r=\frac{1}{2}

Now calculate the ratio for (0,4) and (2,1)

\displaystyle r=\sqrt[2-0]{\frac{1}{4}}

\displaystyle r=\sqrt{\frac{1}{4}}

\displaystyle r=\frac{1}{2}

Testing other points we'll find the same ratio, thus the table is an exponential function

4 0
3 years ago
Read 2 more answers
Please help me solve this practice SAT question!
lord [1]

Answer:

t=5

Step-by-step explanation:

∵ (t,17) lies on (x,y) plane y=x²-3x+7,t>0

∴ 17=t²-3t+7

t²-3t+7-17=0

t²-3t-10=0

t²-5t+2t-10=0

t(t-5)+2(t-5)=0

(t-5)(t+2)=0

t=5,-2

t>0

so t=5

6 0
3 years ago
5x7/8 less than or greater
Pavel [41]
5x7= 35
35> (greater than) 8
5 0
3 years ago
Read 2 more answers
Which is a proportional relationship<br> y=x+1<br> y=3x+3<br> y=4x<br> y=8+x
yulyashka [42]

Answer:

4=4x

Step-by-step explanation:

the formula y=mx+b

corresponds to y=slope+y intercept

all proportional relationships start on the origin so the y-intercept is always 0

the fact that the equation y = 4x doesn't have an intercept shows its proportional this can go with any similar equation like y = 4.5x

8 0
3 years ago
Other questions:
  • Evaluate this 3 times 9 plus 10 times 36/6
    12·1 answer
  • How many months are in 7540 years?
    12·1 answer
  • PLEASE HELP KZKKSOvnfkdjd for sloeidkcncnsk get callallapwd
    9·1 answer
  • I need help with this!!!!!
    15·1 answer
  • I FORGOT HOW TO DO THIS I NEED HELP ASAP!!!
    7·1 answer
  • Solve: 24a - 22 = -4(1 - 6a) HELP PLS HURRY PLS !!!!
    14·1 answer
  • Which of the following survey questions would the least biased?
    15·2 answers
  • Dean wonders if all powders dissolve in water. He decides to see what happens with flour, cornstarch, powdered sugar, and baby p
    5·1 answer
  • What relationship do you notice between the squares of<br> the right triangle?
    6·1 answer
  • "13 more than the product of 4 and a number, n
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!