Recall your d = rt, distance = rate * time.

notice, the distance are the same, say it was "d" miles.

and if car A is travelling at a speed of say "r" mph, then B is going at "r+15" mph.

$\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Car A}&d&r&2\\
\textit{Car B}&d&r+15&1.5
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=2r\\
d=1.5(r+15)\\
----------\\
\boxed{2r}=1.5(r+15)
\end{cases}
\\\\\\
2r=1.5r+22.5\implies 0.5r=22.5\implies r=\cfrac{22.5}{0.5}\implies \boxed{r=\stackrel{mph}{45}}$

how far is B going? well, r + 15.

5 0

3 years ago

Read 2 more answers

Is the answer for number 3 solution or open sentence?

Katen [24]

I believe it's a solution

6 0

3 years ago

Find the distance between points A and C round to the nearest tenth.

Taya2010 [7]

Well the first thing that came to my mind was to do rise/run and doing that I got 6/5 which I added together to get 11 but since that's obviously not correct I assumed it was a little under so the answer I got was 7.8

Really hope this helps!

6 0

3 years ago