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3 years ago

How can you rewrite (20+11) +5

Mathematics

1 answer:

balu736 [363]3 years ago

8 0

Answer:

20 + 11 + 5

or 36

Step-by-step explanation:

(20+11) +5

When we add or subtract you can just get rid of the parenthesis (Unless the negative is before the parenthesis)

20+11+5

When we add them together we get :

31 + 5 = 36

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Help me please quickly

Akimi4 [234]

Answer:

x ≥ 1

Step-by-step explanation:

→ As it is a shaded circle you know it ≤ or ≥

x ≥ 1

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2 years ago

Find the distance between the points (3, -5) and (-6, -5).

Sophie [7]

ANSWER

EXPLANATION

We want to find the distance between the points (3, -5) and (-6, -5).

The given points have the same y-coordinates .

This means it is a horizontal line.

We use the absolute value method to find the distance between the two points.

We find the absolute value of the distance between the x-values.

The distance between the two points is

|3--6|=|3+6|=|9|=9

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3 years ago

Trinity collects rainwater in a cylinder rain barrel. The area of the base of the

Fittoniya [83]

Answer:

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2 years ago

Do you agree with the statement that " cubic functions must have at least 1 x-intercept but not more than 3, whereas quadratic f

vladimir2022 [97]

Answer:

Yes, I agree

Step-by-step explanation:

For the cubic function

A cubic function is represented as:

$f(x)=ax^3+bx^2+cx+d$

A cubic function may have 1, 2 or 3 x intercepts. This is shown below

For 3 x intercepts

$y = x^3 - x$

Equate y to 0

$x^3 - x = 0$

Expand

$x(x^2 - 1) = 0$

Express $x^2 - 1$ as difference of two squares

$x(x - 1)(x +1 ) = 0$

x = 0 or 1 or -1

For 2 x intercepts

$y = x^3 - x$

$y =(x-5)^2)(x+7)$

Equate y to 0

$(x-5)^2(x+7) = 0$

Expand

$(x-5)(x-5)(x+7) = 0$

x= 5 or x = -7

For 1 x intercept

$y = x^3$

Equate y to 0

$x^3 = 0$

Take cube roots of both sides

$x = 0$

It has been shown above that a cubic function may have 1, 2 or 3.

So, I agree to the statement

For the quadratic function

A quadratic function will not have any x intercept when the function can not be factorized;

E.g.

$y = x^2 + x + 17$

The above function has no x intercept.

A quadratic function will have at least 1 x intercept when the function can be factorized;

E.g.

$y = x^2- 6x + 9$

Equate y to 0

$x^2- 6x + 9 = 0$

Expand

$x^2 - 3x - 3x + 9 = 0$

$(x - 3)(x-3) = 0$

$x = 3$

We've shown that a quadratic may have no x intercept, and it may also have x intercept(s)

Hence, I agree to both statement

3 0

2 years ago

factorise the following 1. x²-2x+15.... 2. y²-19y+90

Marta_Voda [28]

Answer:

1. x²-2x+15

This can't be factored, I've tried multiple ways now, but it just can't be factored.

2. y²-19y+90

Let's factor y^2−19y+90

y^2−19y+90

The middle number is -19 and the last number is 90.

Factoring means we want something like

(y+_)(y+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -19

Multiply together to get 90

Can you think of the two numbers?

Try -9 and -10:

-9+-10 = -19

-9*-10 = 90

Fill in the blanks in

(y+_)(y+_)

with -9 and -10 to get...

(y-9)(y-10)

Answer:

(y−9) (y−10)

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3 years ago