Whats the root and vertex for y= 2x squared -5x-604

Mathematics

1 answer:

jeyben [28]3 years ago

6 0

Vertex is calculated by -b/2a

So we have -(-5)/2(2)=5/4

The root is determined through the quadratic formula:

x=(-b+sqrt(b^2-4ac))/2a

x=(-(-5)+sqrt(-5^2-4(2)(-604)))/2(2)

x=(5+sqrt(25-4832))/4

x=(5+sqrt(-4807))/4

So the root is some imaginary number

Hope this helped!

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klasskru [66]

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3 years ago

I need help with this please :)

Marina CMI [18]

9514 1404 393

Answer:

all are Not Equivalent

Step-by-step explanation:

The coefficient of t³ in the target expression is -3. In order for that to be the result of simplifying any of the given expressions, they must have ( )^(t^3) in the denominator. None do, so none of the offered choices is equivalent to the given expression.

_____

The expressions simplify like this:

$\dfrac{(2^3)^{t^3}}{2^{5t}}=2^{3t^3-5t}\\\\\dfrac{8^{t^3}}{32^t}=2^{3t^3-5t}\\\\8^{t^3}\cdot32^t=2^{3t^3+5t}$